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3 years ago

How does 7/8 compare to 8/7?

Mathematics

2 answers:

Crazy boy [7]3 years ago

6 0

Answer:

Step-by-step explanation:

7/8 = 8/7

"Multiplication in x"

7 x 7 = 49

8 x 8 = 64

---------------------------

7/8 -> 49

8/7 -> 64

Crazy boy [7]3 years ago

3 0

Answer: Not sure if this is what you mean, but 7/8 < 8/7

Step-by-step explanation:

In 7/8, the numerator is smaller than the denominator, so the fraction is less than 1. In 8/7, the numerator is greater than the denominator, so the fraction is greater than 1. Thus, 8/7 > 7/8.

<em>Hope it helps <3</em>

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Step-by-step explanation: the slope is calculated by the formula:

(y2 - y1)/(x2-x1)

So, (-1-8)/(-3-(-9)) = -9/6 = -3/2

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3 years ago

Read 2 more answers

Let f(x)=2/x-3. Find f^-1(x)

KonstantinChe [14]

Answer:

Two questions:

Question 1: $f^{-1}(x)=?$ given $f(x)=\frac{2}{x}-3$ .

Answer 1: $f^{-1}(x)=\frac{2}{x+3}$

Question 2: $f^{-1}(x)=?$ given $f(x)=\frac{2}{x-3}$ .

Answer 2: $f^{-1}(x)=\frac{2}{x}+3$

Step-by-step explanation:

So $f^{-1}$ is used in most classes to represent the inverse function of $f$ .

The inverse when graphed is a reflection through the y=x line. The ordered pairs $(a,b)$ on $f$ implies $(b,a)$ are on $f^{-1}$ .

This means we really just need to swap x and y.

Since we want to write as a function of x we will need to solve for y again.

Question 1:

$y=\frac{2}{x}-3$

Swap x and y:

$x=\frac{2}{y}-3$

We want to solve for y.

Add 3 on both sides:

$x+3=\frac{2}{y}$

Make the left hand side a fraction so we can cross-multiply:

$\frac{x+3}{1}=\frac{2}{y}$

Cross multiply:

$y(x+3)=1(2)$

Simplify right hand side:

$y(x+3)=2$

Divide both sides by (x+3):

$y=\frac{2}{x+3}$

So $f^{-1}(x)=\frac{2}{x+3}$ .

Question 2:

$y=\frac{2}{x-3}$

Swap x and y:

$x=\frac{2}{y-3}$

Make left hand side a fraction so we can cross multiply:

$\frac{x}{1}=\frac{2}{y-3}$

Cross multiply:

$(y-3)x=1(2)$

We have to distribute here:

$yx-3x=2$

Add 3x on both sides:

$yx=2+3x$

Divide boht sides by x:

$y=\frac{2+3x}{x}$

You could probably stop here but you could also simplify a little.

Separate the fraction into two terms since you have 2 terms on top bottom being dividing by x:

$y=\frac{2}{x}+\frac{3x}{x}$

Simplify second fraction x/x=1:

$y=\frac{2}{x}+3$

So $f^{-1}(x)=\frac{2}{x}+3$ .

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3 years ago

there is 90 5th grade students going on a field trip. each student gives the teacher $9.25 to cover admission to the theater and

Allisa [31]

(9.25x90-315)/90
(832.5-315)/90
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3 years ago