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2 years ago

If you’re good at geometry could somebody help me with this?

Mathematics

2 answers:

almond37 [142]2 years ago

6 0

Answer:

The pentagon

Step-by-step explanation:

It is the only shape out of the four that is not a quadrilateral. While every other choice has four sides, the pentagon has five.

An argument could also be made for the gray square. It is the only one that is not colored white on the inside.

andrew11 [14]2 years ago

4 0

The pentagon does not belong because it has 5 sides while the other 3 shapes have only 4 sides.

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

3 years ago

Wendy stops running<br> A.Speed<br> B.Velocity <br> C.Acceleration

DedPeter [7]

Answer:

i think is c tell me if im right

7 0

2 years ago

Read 2 more answers

Calculate the length of AC to one decimal place in the trapezium below.

a_sh-v [17]

Answer:

First we will split trapezium on two geometric figure.

One is rectangle and the second is right triangle.

When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.

We will use Pythagorean theorem to find the second cathetus b

b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>

AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm

AC=18.1cm

Good luck!!

7 0

2 years ago

Solve the amount in picture

ss7ja [257]

It’s 2/25 because 24 x 1/3/100 and you simplify the complex fraction so it’s 24 x 1/300 now reduce the numbers with the greatest common factor 12 so now it’s 2x1/25 then calculate the product 2/25

5 0

2 years ago

Three lights all go on one changes every 5 sec one every 6 sec one every 8 sec when will they all go on together

inysia [295]

In order to calculate, you need to find their LCM
LCM of 5,6 and 8 is equal to 120

So, That time will be 120 sec = 2 min.
In short, Your Final Answer would be 2 min.

Hope this helps!

3 0

3 years ago