Okay. So, she buoyant 5.65 lbs of roast beef for $4.50. Multiply both of those numbers to get 25.425 or 25.43 when rounded to the nearest hundredth. So the total cost was $25.43. However, we now have to divide the amount by 6.5. 25.43/6.5 is 3.912 and other odd numbers or 3.91 when rounded to the nearest hundredth. The cost per sandwich was $3.91.
Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
99.69/100=.9969
.9969*20=19.938
Ramon would receive ~ $19.94
About 379.1666666666666
The 6 is repeating. Or about 379 if your rounding.
Hello from MrBillDoesMath!
Answer: b
Discussion:
7b + 3 - 4b = 3 - 3(b+4) =>
7b + 3 - 4b = 3 - 3b -12 =>
(7b - 4b) + 3 = -3b - 9 =>
3b + 3 = -3b -9 => Add 9 to both sides
3b + 12 = -3b -9 + 9 =>
3b + 12 = -3b => ( add 3b to both sides)
6b + 12 = 0 => (subtract 12 from both sides)
6b = -12 =>
b = -12/6 = -2
Thank you,
MrB
