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horsena [70]
3 years ago
14

Write the IUPAC and common names, if any, of the carboxylate salts produced in the reaction of each of the following carboxylic

acids with NaOH: 2-methylhexanoic acid
Part A
2-bromopropanoic acid Spell out the full name of the compound. If there is a common name separate your answers by a comma.
Part B
2-methylhexanoic acid Spell out the full name of the compound. If there is a common name separate your answers by a comma.
Chemistry
1 answer:
Tems11 [23]3 years ago
5 0

Answer:

Following are the explanation to this question:

Explanation:

The salts of carboxylate are named by the writing, which is also named as the creation of the first, which is followed by the name of the carboxylic acid were '-ic' of the acid end and replaced by the 'ate'.

Following are the description of the given reaction:

In reaction A:

2-Bromopropanoic acid= C_3H_5BrO_2

C_3H_5BrO_2+NaOH⇄ C_3H_4BrNaO_2 +H_2O

The IUPAC name is Sodium-2-Bromopropanate

In reaction B:

2-Methylhexanoic acid= C_7H_{14}O_2

C_7H_{14}O_2+NaOH⇄ C_7H_{13}NaO_{2}+H_2O

The IUPAC name is Sodium-2-Methyl hexanoate

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