Answer: 2 atoms
Explanation: A molecular formula of the compound carbon dioxide is CO 2 . One molecule of carbon dioxide consists of 1 atom of carbon and 2 atoms of oxygen.
Answer:
40 electrons
Explanation:
The element of zirconium (Zr) has an atomic number of 40, which means it has 40 protons and 40 electrons. It also has a molar mass of 91.224 g/mol.
Answer:
4.occupy a definite volume while taking the shape of their container.
Explanation:
Since the particles in a liquid are quite close together (not as close as a solid) they have a definete volume, and the particles are still able to move around as they wish they have no definite shape and take upon the shape of the container they are placed in.
Explanation:
The given reaction equation will be as follows.
![[FeSCN^{2+}] \rightleftharpoons [Fe^{3+}] + [SCN^{-}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%5Crightleftharpoons%20%5BFe%5E%7B3%2B%7D%5D%20%2B%20%5BSCN%5E%7B-%7D%5D)
Let is assume that at equilibrium the concentrations of given species are as follows.
![[Fe^{3+}] = 8.17 \times 10^{-3}](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%20%3D%208.17%20%5Ctimes%2010%5E%7B-3%7D)
M
![[SCN^{-}] = 8.60 \times 10^{-3}](https://tex.z-dn.net/?f=%5BSCN%5E%7B-%7D%5D%20%3D%208.60%20%5Ctimes%2010%5E%7B-3%7D)
M
![[FeSCN^{2+}] = 6.25 \times 10^{-2}](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%3D%206.25%20%5Ctimes%2010%5E%7B-2%7D)
M
Now, first calculate the value of 
as follows.
![K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BFe%5E%7B3%2B%7D%5D%5BSCN%5E%7B-%7D%5D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
= 
= 
Now, according to the concentration values at the re-established equilibrium the value for ![[FeSCN^{2+}]](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D)
will be calculated as follows.
![11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}](https://tex.z-dn.net/?f=11.24%20%5Ctimes%2010%5E%7B-4%7D%20%3D%20%5Cfrac%7B8.12%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%207.84%20%5Ctimes%2010%5E%7B-3%7D%7D%7B%5BFeSCN%5E%7B2%2B%7D%5D%7D)
![[FeSCN^{2+}] = 5.66 \times 10^{-2}](https://tex.z-dn.net/?f=%5BFeSCN%5E%7B2%2B%7D%5D%20%3D%205.66%20%5Ctimes%2010%5E%7B-2%7D)
M
Thus, we can conclude that the concentration of in the new equilibrium mixture is 
M.
Answer:
The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.
Explanation:
Given data:
Atomic mass of silicon= ?
Percent abundance of Si-28 = 92.21%
Atomic mass of Si-28 = 27.98 amu
Percent abundance of Si-29 = 4.70%
Atomic mass of Si-29 = 28.98 amu
Percent abundance of Si-30 = 3.09%
Atomic mass of Si-30 = 29.97 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100
Average atomic mass = 2580.04 +136.21+92.61 / 100
Average atomic mass = 2808.86 / 100
Average atomic mass = 28.08amu.
The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.
