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swat32
2 years ago
9

Nitromethane (CH3NO2) is an explosive compound sometimes used as a fuel booster in racecars. What is the formal charge of the ni

trogen in a nitromethane molecule?
a. -2
b. -1
c. 0
d. +1
Chemistry
1 answer:
nevsk [136]2 years ago
5 0

Answer:

Option d. is correct

Explanation:

Nitromethane is an organic compound that can be used as a fuel booster in rockets. Its chemical formula is CH_3NO_2.

This compound is produced as a result of reaction of sodium chloroacetate with sodium nitrite in aqueous solution.

The electron-dot structure of a nitromethane molecule shows +1 charge on the nitrogen.

Option d. is correct

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A student observes the combustion (burning) of propane (C3H8). Because of the heat and light it generates, the student concludes
insens350 [35]

Answer:

The student's conclusion is not correct

Explanation:

Activation energy is the minimum amount of energy required for a reaction to occur. All reactions require there activation energy to be met before the reaction can proceed. When the temperature of a reaction is increased, the kinetic energy of the reactant molecules increases; colliding more with each other, which makes them "surmount" the activation energy of the reaction faster as compared to a lower temperature.

In combustion, there is burning of an hydrocarbon (in this case propane) in excess oxygen. The burning assists in increasing the kinetic energy of the reactant particles which in turn easily surmounts the activation energy of the reaction  by colliding (effective collision) more with oxygen. So, the reaction has an activation energy but the activation energy has been met and passed and hence the reaction is proceeding faster.

Increasing the temperature of a reaction is one of the ways of increasing the rate of a chemical reaction.

7 0
2 years ago
Which of these statements is not true?question 20 options:atoms of isotopes of an element have different numbers of protons.atom
Greeley [361]
The first one is the answer
isotopes of an atom have different number of neutrons . the number of protons are not different in isotopes of an atom
4 0
2 years ago
Read 2 more answers
A gas effuses 4.0 times faster than oxygen (o2). what is the molecular mass of the gas? 1.0 g/mol 1.0 g/mol 2.0 g/mol 2.0 g/mol
Anastaziya [24]

Answer:

32(molecular mass has no unit )

Explanation:

(16)(o2)

16×2

=32

5 0
2 years ago
Based on the balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O calculate the number of excess reagent units remaining when 52 C2H2 mol
erica [24]

Answer:

20 molecules of oxygen gas remains after the reaction.

Explanation:

2C_2H_2 + 5O_2\rightarrow 4CO_2 + 2H_2O

Molecules of ethyne = 52

Molecules of oxygen gas = 150

According to reaction, 2 molecules of ethyne reacts with 5 molecules of oxygen gas.

Then 52 molecules of ethyne will react with:

\frac{5}{2}\times 52=130 molecules of oxygen gas.

As we can see that we have 150 molecules of oxygen gas, but 52 molecules of ethyne will react with 130 molecules of oxygen gas. So, this means that ethyne is a limiting reagent and oxygen gas is an excessive reagent.

Remaining molecules of recessive reagent = 150 - 130 = 20

20 molecules of oxygen gas remains after the reaction.

5 0
3 years ago
Given that 25.0 mL of mercury has a mass of 340.0 g, calculate (a) the density of mercury and (b) the mass of 120.0 mL of mercur
natita [175]

Answer :

(a) The density of mercury is, 13.6 g/ml

(b) The mass of 120.0 ml of mercury is, 1632 grams

Explanation :

(a) Now we have to calculate the density of mercury.

<u>Given :</u>

Volume of mercury = 25.0 ml

Mass of mercury = 340.0 g

Formula used :

\text{Density of mercury}=\frac{\text{Mass of mercury}}{\text{Volume of mercury}}

\text{Density of mercury}=\frac{340.0g}{25.0ml}=13.6g/ml

Therefore, the density of mercury is, 13.6 g/ml

(b) Now we have to calculate the mass of 120.0 ml of mercury.

As, 25.0 ml of mercury has mass = 340.0 g

So, 120.0 ml of mercury has mass = \frac{120.0ml}{25.0ml}\times 340.0g=1632g

Therefore, the mass of 120.0 ml of mercury is, 1632 grams

3 0
3 years ago
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