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3 years ago

PLZ HELP

Chemistry

2 answers:

shusha [124]3 years ago

5 0

Use the equation for density :
Density = mass / volume
Density = 120 / 480
Density = 0.25

SashulF [63]3 years ago

5 0

Answer:

Density = 0.25 g/cm³

Explanation:

Firstly, the density of a body is the mass of that body divided by it volume. The density gives the idea of the relationship between the mass of a body and the space which it occupies(volume). How tightly packed the atoms that makes up the body, affects the density of every substance. If the substance has a large mass and the atoms are well arrange to fill all the spaces the density is expected to be high.

In the case of fire wood that has life initially, due to the sparsely packed nature of the cells the firewood is bound to have a low density because the mass are not occupying as much space as possible.

The mass of the firewood is already measured and known likewise the volume. Base on the formula for calculating density which is ;

Density = mass/volume

Density = 120/480

dividing through

Density = 1/4

converting the fraction to decimal

Density = 0.25 g/cm³

The density of the firewood is 0.25 gram per centimeter cube

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Answer:

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Explanation:

Step 1:

Data obtained from the question.

First experiment:

Mass of the compound = 36.165 mg

Mass of CO2 = 64.425 mg

Mass of H2O = 26.373 mg

Second experiment:

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Mass of SO2 = 20.32 mg

Step 2:

Determination of the mass of C, H and S. This is illustrated below:

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Mass of S in SO2 = 32/64 x 20.32

Mass of S = 10.16 mg

Step 3:

Determination of the the percentage composition of C, H, S and O. This is illustrated below:

% of C = 17.57/36.165 x 100 = 48.58%

% of H = 2.93/36.165 x 100 = 8.10%

% of S = 10.16/47.029 x 100 = 21.60%

% of O = 100 - (48.58 + 8.1 + 21.6)

% of O = 21.72%

Step 4:

Divide by their molar mass

C = 48.58x10^-3/12 = 4.0483

H = 8.10/1 = 8.1

S = 21.60/32 = 0.675

O = 21.72/16 = 1.3575

Step 5:

Divide by the smallest:

C = 4.0483/0.675 = 6

H = 8.1/0.675 = 12

S = 0.675/0.675 = 1

O = 1.3575/0.675 = 2

Therefore, the empirical formula is C6H12SO2

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3 years ago