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MaRussiya [10]
3 years ago
10

Anybody know the answer for this ?asking for a friend

Mathematics
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

B. Congruent - SAS

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35% of 15=35/100×15=21/4=5.25

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the vate rate of a country is 15% ,a woman bought an item with a price tag ghc 300 plus vat .what price did she pay for the item
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Step-by-step explanation:

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2 years ago
What is the value of x? enter your answer in the box x= <br>​
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<h3>the horizontal value in a pair of coordinates: how far along the point is. the x coordinate is always written first in an ordered pair of coordinates (x,y) such as (12,5). in this example, the value "12" is the x coordinate. also called abscissa</h3>

Step-by-step explanation:

i hope it helps :)

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A large container holds 5 gallons of water. It begins leaking at a constant rate. After 10 minutes, the container has 3 gallons
borishaifa [10]
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6 0
4 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
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