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sergejj [24]
3 years ago
7

A number is divided by 2, and then 8 is subtracted from the quotient. The result is 16. What is the number?

Mathematics
2 answers:
rodikova [14]3 years ago
8 0

Answer: x = 48

Step-by-step explanation:

(x / 2) - 8 = 16

1/2x - 8 = 16

x - 16 = 32

x = 32 + 16

x = 48

Vinvika [58]3 years ago
3 0

Answer:

x=48.

Step-by-step explanation:

First let's make an equation out of this.

x

--   -   8   =    16

2

The first thing that we do it add 8 on both sides of the equation. So now we have.

x

--   =  24

2

Up next is to multiply 2 by both sides of the equation so that we get the equation of...

x = 48.

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8 0
3 years ago
Length of a rectangular prism is increased by factor of 1.5. The width is doubled and height is tripled. What is the new volume?
dimulka [17.4K]

Nine times the original volume

Step-by-step explanation:

Let the length, width and height of the rectangular prism be 'l' 'w' and 'h'.

The volume of the rectangular prism is given by,

V = W x l x h

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V = wlh

Here the length is 1.5 the original length

So, l = 1.5 x l = (1.5l)

And the with is doubled. So,

W = 2W

The height is tripled. So,

h = 3h

Volume of the new rectangular prism is,

V = (1.5l) (2w) (3h)

V = 9 wlh

We know that wlh is the original volume of the rectangular prism.

So the new volume is 9 times the original volume.

4 0
3 years ago
The area of a football field can be calculated
pashok25 [27]
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5 0
3 years ago
Find the exact value of each trigonometric function for the given angle θ.
Kay [80]

Answer:

\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since \theta=240, it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}

\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}

\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}

\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}

\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2

\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}

Therefore, \sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.

8 0
3 years ago
Explain how to create a translation
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By translating a shape, you are basically moving it around the graph. For example, one of the points of your shape could be on the origin (0,0). You could then translate it 4 units up and 6 units to the left. You would write this translation as (x-6, y+4). If you were starting at (0,0) your point translation would be at (-6, 4), but if you were to translate a point at (1, 1) your translated point would be at (-5, 5).
7 0
3 years ago
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