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Kitty [74]
3 years ago
9

(-4, -5) (3, 4) Slope:

Mathematics
1 answer:
Ivan3 years ago
5 0

Answer    

<em>1.M=1</em>

<em>2.3/5</em>

<em>3.</em>(NO SOLUTION)

<em>4.0</em>

<em>5.</em>1/2 =0.5

Step-by-step explanation:

<u>Y=mx+b </u>

<u>M=(Y2)+(y1)/(x2)+(x1)</u>

1. x1  y1    x2   y2

    (-4 , -5) , (3 , 4)

Slope:

M=(4)+(-5)/(3)+(-4)

=-1/-1= 1

2. x1  y1    x2   y2

    (0 , -2) , (5, -1)

Slope:

M=(-1)+(-2)/(5)+(0)

=-3/5

3. x1  y1    x2   y2

    (-5 , -1) , (5 , -3)

Slope:

M=(-3)+(-1)/(5)+(-5)

=- 4/0=(NO SOLUTION)

4. x1  y1    x2   y2

    (-5, -5) (-1, 5)

Slope:

M=(5)+(-5)/(-1)+(-5)

= 0/-6 =0

5. x1  y1    x2   y2

    (-2, 0) (4, 1)

Slope:

M=(1)+(0)/(4)+(-2)

= 1/2 =0.5

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A circle has end points (-2,1) and (8,3).
Drupady [299]

Answer:

A) find its center  = (3, 2)

B) find the radius of the circle = √104

C) find the equation of the circle = x² + y² - 6x - 4y -91 = 0

Step-by-step explanation:

A)- The center must be the mid-points of (-2, 1) and (8, 3).

So, using the equation of mid-point,

h=\frac{x_{1}+x_{2}}{2}  and  k=\frac{y_{1}+y_{2}}{2}

Here, (x₁, y₁) = (-2, 1) and (x₂, y₂) = (8, 3)

Putting these value in above equation. We get,

h = 3 and k = 2

Thus, Center = (h, k) = (3, 2)

B)- For finding the radius we have to find the distance between center and any of the end point.

Thus using Distance Formula,

Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Radius =\sqrt{(8+2)^{2}+(3-1)^{2}}

⇒ Radius = √104 = 2√26

C)- The equation of circle is determined by formula:

(x-h)^{2}+(y - k)^{2} = r^{2}

where (h, k ) is center of circle and

r is the radius of circle.

⇒ (x - 3)² + (y - 2)² = 104

⇒ x² + y² - 6x - 4y -91 = 0

which is the required equation of the circle.

8 0
3 years ago
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