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3 years ago

Identify the glide reflection rule in the given figure

Mathematics

1 answer:

Maslowich3 years ago

4 0

Answer:

Option (3)

Step-by-step explanation:

Glide reflection of a figure is defined by the translation and reflection across a line.

To understand the glide rule in the figure attached we will take a point A.

Coordinates of the points A and A' are (2, -1) and (-2, 4).

Translation of pint A by 5 units upwards,

Rule to be followed,

A(x, y) → A"[x, (y + 5)]

A(2, -1) → A"(2, 4)

Followed by the reflection across y-axis,

Rule to be followed,

A"(x, y) → A'(-x, y)

A"(2, 4) → A'(-2, 4)

Therefore, by combining these rules in this glide reflections of point A we get the coordinates of the point point A'.

Option (3) will be the answer.

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Tori spends equal amounts of time on homework from each of her subjects. She spends 1 hour altogether on her homework each night

Montano1993 [528]

Answer:

Step-by-step explanation:

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3 years ago

Convert these decimals and SIMPLIFY: .12 .250 .3 .85 .300 .05

melisa1 [442]

Answer:

.12 = 12/100 or 4/25 I'm not sure if I'm correct but I tried, I'll try solving the other ones and update you

.250 = 25/100 which simplified is 5/20

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3 years ago

Read 2 more answers

Solve with matrices. 5x -3y = 18 and 2x + 7y = -1

muminat

We'll use Cramer's rule for 2 equations:

ax + by = e

cx + dy = f

5x -3y = 18 a=5 b=-3 e=18

2x + 7y = -1 c=2 d=7 f=-1

denominator determinant (dn) = (a * d) - (c * b) = 5 * 7 - (2 * -3) = 41

x = [(e * d) - (f * b)] / dn

[18 * 7 - (-1 * -3)] / 41 =

123 / 41 = 3

y = [(a * f) - (c * e)] / dn

= (5 * -1) -(2 * 18) / 41 =

-41 / 41 = -1

Source:

1728.com/cramer.htm

6 0

3 years ago

9/20

NISA [10]

For this case we must find the solution of the following quadratic equation:

$x ^ 2 + 5x + 7 = 0$

Where:

$a = 1\\b = 5\\c = 7$

Then, the solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values:

$x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}$

By definition we have: $i ^ 2 = -1$

$x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}$

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0

4 years ago

What is the solution of x=2+√x-2 ?

Blizzard [7]

C. \: x = 2 \: or \: x = 3

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3 years ago