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2 years ago

15

For what values of x is x2+2x=24 true?

2 answers:

JulijaS [17]2 years ago

5 0

Answer:

$x=-6$ and $x=4$

Step-by-step explanation:

We must solve the quadratic equation to find the values of x that satisfy equality

$x^2+2x=24$

Subtract 24 on both sides of equality

$x^2+2x-24=24-24$

$x^2+2x-24=0$

Now we factor the quadratic equation

Identify two numbers that when you add them you get as a result 2 and when you multiply them you get as a result -24

The numbers sought are: 6 and -4

So the factors are:

$(x+6)(x-4)=0$

Finally note that the solutions are:

$x=-6$ and $x=4$

Blababa [14]2 years ago

5 0

Answer:

The answer is C). 4 and-6

Step-by-step explanation:

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Sketch the graph of each line

adoni [48]

Answer:

(0,5) (1,0)

Step-by-step explanation:

Place your first dot on the 5 (0,5) of the y-axis (The one that is vertical) from there count down the line one value at a time until you have counted DOWN 5 times. Go to the right once and place another point there (1,0). Then draw a straight line that connects those two points.

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2 years ago

Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.

il63 [147K]

Answer:

The minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

Step-by-step explanation:

Given function is $f(x) = 0.15(x + 1)^2 - 3$

We need to find the maximum value or the minimum value for the function.

Now, differentiate $f(x) = 0.15(x + 1)^2 - 3$ w.r.t $x$ .

$f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\$

$f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)$

Now, we will equate $f'(x)=0$ to find critical point.

$0.3(x+1)=0\\x=-1$

Plug this critical point in to the function $f(x) = 0.15(x + 1)^2 - 3$ we get,

$f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3$

Also, $f''(x)=0.3$ which is positive, We have minimum value.

So, the minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

7 0

3 years ago

Help me plz I'm stuck

Lelechka [254]

The answer to one would be 25534

3 0

2 years ago

Choose the statements that are true about a cube with side length 1 unit. It can be used to measure volume. It has a volume of 6

daser333 [38]

Answer:

it has a volume of 1 cubic unit. its called a "unit block"

Step-by-step explanation:

4 0

2 years ago

Given the function h(a) = -x^2+ 7x + 14, determine the average rate of change

Yakvenalex [24]

Answer:

- 2

Step-by-step explanation:

The average rate of change of h(x) in the closed interval [a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [a, b ] = [1, 8 ], thus

f(b) = f(8) = - 8² + 7(8) + 14 = - 64 + 56 + 14 = 6

f(a) = f(1) = - 1² + 7(1) + 14 = - 1 + 7 + 14 = 20

average rate of change = $\frac{6-20}{8-1}$ = $\frac{-14}{7}$ = - 2

6 0

2 years ago