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2 years ago

12

Find 2u - 3v. u=6i, v=j a. 121-3j b.6i-j c. 12i+3j d.6i-3j e. -12i-3j

1 answer:

ohaa [14]2 years ago

8 0

Answer:

2u - 3v = 12i- 3j/C

Step-by-step explanation:

So it says U = 6i, if you do 2 x 6i you get 12 i

Then 3 x v which is j gets you 3 j

If you add the 2 answers together you get 12i - 3j

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2 years ago

Multiply 60 times 7 410, 420, 67, or 430?

DochEvi [55]

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Step-by-step explanation:

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2 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time

cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

$1\leq t\geq \sqrt{2}$

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

$h =20-5t^{2}$ -----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height $h = 15m$

Put height value in equation 1

$15 =20-5t^{2}$

$5t^{2} =20-15$

$5t^{2} =5$

$t^{2} =1$

$t =\pm1$

We know that the time is always positive, therefore $t=1$

when the stuntman is 10m above the ground.

height $h = 10m$

Put height value in equation 1

$10 =20-5t^{2}$

$5t^{2} =20-10$

$5t^{2} =10$

$t^{2} =\frac{10}{5}$

$t^{2} =2$

$t=\pm\sqrt{2}$

$t=\sqrt{2}$

Therefore ,time interval of camera film him is $1\leq t\geq \sqrt{2}$

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3 years ago

If Andrea makes $10 per hour and Cassidy makes eight dollars per hour how much more by percent does Andrea make than Cassidy per

Alexus [3.1K]

Hey there!

Andrea makes 20% more than Cassidy.

Work:

10 x 0.20 = 2

10 - 2 = 8

So that proves it is 20%.

Hope this helps!

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2 years ago

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Answer:

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Step-by-step explanation:

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Y-intercept is 50

y = 8x + 50

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