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2 years ago

WILL GIVE BRAINLIEST PLEASEEEEEE HELP algebra one !!!!!!

Mathematics

1 answer:

Vsevolod [243]2 years ago

6 0

9.
Blank 1: 4
Blank 2:2
Blank 3:3

The area of a rectangle is equal to its width times its length. To find the width given the area, divide the area by the length. I’ll break this down for each term...

(48x^3y^7) / (12xy^4)
48/4=12
X^3 / X = X^2 (subtract exponential values when dividing)
Y^7 / Y^4 = Y^3 (subtract exponential values when dividing)

10.
Blank 1: 2
Blank 2: x^9
Blank 3: y^3
Blank 4: z^5

To find the length of the cube when given the volume, divide by the product of the width and height (heigh times width).
The product of the width and the height is 30x^7y^6.

60/30=2
X^16/x^7=x^9
Y^9/y^6=y^3
Z^5/1=z^5

Please mark brainliest if this helped! Feel free to ask any questions in the comments as well. Hope this helps! ;)

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2 years ago

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

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