Answer:
Step-by-step explanation:
I can't make specific statements about the proof because the midpoint is missing.
Givens
There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.
MN is bisected by the point on MN where the perpendicular meets MN
The Perpendicular Bisector is is common to both triangles.
Therefore the two triangles are congruent by SAS
PM = PN Parts contained in Congruent triangles are congruent.
Answer:
5 4 3 2 1 0 -1 -2 -3 -4 -5
Step-by-step explanation:
Answer:
BC < ED ⇒ answer A
Step-by-step explanation:
* Lets revise some facts in the triangle
- If one side of a triangle is longer than another side, then the angle
opposite the longer side will be larger than the angle opposite the
shorter side
- If one angle in a triangle is larger than another angle in a triangle,
then the side opposite the larger angle will be longer than the side
opposite the smaller angle
* Lets solve the problem
- In the two triangles BCD and DEB
∵ CD = 8 and BE = 8
∴ CD = BE
∵ Side BD is a common side in the two triangles
- The third side in Δ BCD is BC and the third side in DEB is DE
∵ BC is the opposite side to the angle of measure 24°
∵ ED is the opposite side to the angle of measure 30°
∵ The measure 24° < the measure 30°
∴ The side opposite to the angle of measure 24° < the side opposite
to the angle of measure 30°
∵ The other two sides of the 2 triangles BCD and DEB are equal
∴ We can compare between the 3rd sides in the Δ BCD and Δ DEB
∴ BC < ED
Hello,
n=1,2,3,.... and not 0
Answer B a(n)=-2*n
the sign would probably be a negative. imagine this - - - - - - and then + + +, cancel out the negatives and plus then you are left with more negatives than positive so the sign will take the negative sign.
