Question

The voltage is 27/125 and it has been reduced 3 times. What is the original voltage in the circuit?

Answer 1

Answer:

The original voltage in the circuit is $\frac{81}{125}$

Step-by-step explanation:

We are given

Current voltage is

$V_c=\frac{27}{125}$

Let's assume original voltage as Vo

we are given

it has been reduced 3 times

so,

$V_c=\frac{V_o}{3}$

we can plug values

$\frac{27}{125}=\frac{V_o}{3}$

Multiply both sides by 3

$\frac{27}{125}\times 3=\frac{V_o}{3}\times 3$

$\frac{81}{125}=V_o$

$V_o=\frac{81}{125}$

So,

The original voltage in the circuit is $\frac{81}{125}$