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Zielflug [23.3K]
3 years ago
7

Which angle is adjacent to _DFE? ZAFB ZAFC OBFD _BFC

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

zafb

Step-by-step explanation:

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Write the following relationship as a ratio in simplest form. 18 students out of 42 students
ioda

Answer:

3:7

Step-by-step explanation:

18/6(largest factor)=3

42/6(largest factor)=7

3 0
3 years ago
Read 2 more answers
Hello someone please help me
Naya [18.7K]

Answer:

(2, -8)

Step-by-step explanation:

6 0
2 years ago
Identify one solution for this graph
sp2606 [1]
(0,0), (1,1)
Basically, any point that is shaded.
7 0
2 years ago
please just give me the answer is homework please help1)vertex 2)axis of symmetry 3)x-intercepts 4)maximum or minimum 5)max/min
aniked [119]

Answer:

See explanations below

Explanation:

Vertex of a graph is the lowest point on the curve. The vertex occurs at (1.75, -2.5)

The axis of symmetry is the point on the x axis of the line that cuts through the minimum point. The axis of symmetry occurs at x = 1.75

x intercept is the point where the curve cuts the x axis. The x intercept occurs at x = 0 and x = 2.5

To get the minimum, we will use the formula;

c - b^2/4a

The equation of the curve is expressed as;

(x-0)(x-2.5)

= x (x-2.5)

= x^2 - 2.5x

a = 1, b = -2.5, c = 0

minimum = 0 - (-2.5)^2/4(1)

minimum = -6.25/4

minimum = -1.5625

Minimum value occurs at the base of the parabola. The minimum value of the function is -2.5

y intercept is the point where the curve cuts the y axis. The y-intercept occurs at y = 0.

6 0
1 year ago
Write the complex number -2+2i in polar form
FromTheMoon [43]
For polar form you need to find the modulus (length of the vector) and the argument (angle of the vector) and present in form rcis(Arg) or re^Argi

start with the modulus r=sqrt(a^2 +b^2)
                                     =sqrt(-2^2 +2^2)
                                     = sqrt(4+4)
                                     =sqrt(8)
                                     =2sqrt(2)

next the argument, firstly arg=tan(b/a)
                                              = tan(2/2)
                                              =tan(1)
                                             =pi/4 .     (exact values table)
Now consider the quadrant the complex number is in, as it is (-2,2) it is in the second quadrant and as such your Arg value is:
Arg=pi-arg
     = pi-pi/4
     = 3pi/4

add it all together and your complex number in polar form is:
2sqrt2cis(3pi/4)

note: cis is short hand for cos(x)+isin(x), it is possible your tutor would rather you use the complex exponential form which is simply re^Argi and your answer would look like:
2sqrt2e^(3pi/4)i

Also notice the difference between arg and Arg as this often slips students up and always present Arg in prinicple argument form ie -pi<Arg<pi

Hopefully this has been clear enough and good luck

8 0
2 years ago
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