Answer:
a² + 16a - 612 = 0
Step-by-step explanation:
Here is the complete question :
The width of an extra large rectangle poster is 8 inches more than half its length. The area of this poster is 306 square inches
Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster.
Area of a rectangle = length x width
Let length = a
width = 8 + 1/2a
Area = (8 + 1/2a) x a
306 = (8 + 1/2a) x a
multiply both sides of the equation by 2
612 = 16a + a²
a² + 16a - 612 = 0
the dimensions of the poster can be determined using quadratic formula
Answer:
155
Step-by-step explanation:
Answer:
8
Step-by-step explanation:
A2+B2=C2
A2+15squared=17squared
A2+225=289
289-225=64
A2=64
64 squared is 8
For this case we will define the following:
A, B: are the values of the triangle angles
a, b: are the values of the lengths of the sides opposite the angles A, B.
We then have to use the law of the sine:

Clearing the angle B we have:

Substituting values we have:
Answer:
the following is true:
A. angle B=38.08 degrees