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Nataliya [291]
2 years ago
8

Find the area of the shape shown below. 12 units

Mathematics
1 answer:
Lelechka [254]2 years ago
8 0

Answer:

32

Step-by-step explanation:

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The width of an extra large rectangle poster is 8 inches more than half its length.The area of this poster is 306 square inches
maria [59]

Answer:

a² + 16a - 612 = 0

Step-by-step explanation:

Here is the complete question :

The width of an extra large rectangle poster is 8 inches more than half its length. The area of this poster is 306 square inches

Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster.

Area of a rectangle = length x width

Let length = a

width = 8 + 1/2a

Area =  (8 + 1/2a) x a

306 =  (8 + 1/2a) x a

multiply both sides of the equation by 2

612 = 16a + a²

a² + 16a - 612 = 0

the dimensions of the poster can be determined using quadratic formula

8 0
2 years ago
Find the Median of <br> 140, 150, 160, 170 <br> Help?
Nikolay [14]

Answer:

155

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Multiply or divide. Write your answers in simplest form. 2/3 x 3/4, 3/5 divided by 1/2, 5 Divided by 3/8, 3/7 x 4/3, 4/9 divided
Yanka [14]
X/2, 6/5, 40/3,4x/7,20/27
7 0
3 years ago
PLS HELP ILL GIVE BRAINLIST!
lyudmila [28]

Answer:

8

Step-by-step explanation:

A2+B2=C2

A2+15squared=17squared

A2+225=289

289-225=64

A2=64

64 squared is 8

7 0
2 years ago
URGENT! Please and Thanks :)
eimsori [14]
For this case we will define the following:
 A, B: are the values of the triangle angles
 a, b: are the values of the lengths of the sides opposite the angles A, B.
 We then have to use the law of the sine:
 \frac{sinB}{b} = \frac{sinA}{a}
 Clearing the angle B we have:
 sinB = \frac{sinA}{a}*b
 B = arcsin(\frac{sinA}{a}*b)
 Substituting values we have:
 B = arcsin(\frac{sin113}{200}*134)
 B = 38.08
 Answer:
 
the following is true:
 
A. angle B=38.08 degrees 

6 0
2 years ago
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