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Vanyuwa [196]
3 years ago
10

Mark is building a custom wooden frame around his flower bed. The length of the frame is 5.45 feet ,and the width of the frame i

s 3.275. What is the area of the flower bed without rounding?
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

17.84875

Step-by-step explanation:

5.45 x 3.275 = 17.84875

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Evaluate (-A)^2 for A = 5, B = -4, and C = 2
drek231 [11]

Answer:

(-A)^2 for A = 5

(-5)^2

=25

Step-by-step explanation:

first, replace A by 5, and maintain the negative to the 5.

multiply (-5)^2.

nb: don't forget to maintain the bracket when multiplying. if you maintain the bracket, you'll get a positive number, but if you don't, you'll get a negative number.

6 0
3 years ago
Over the last 3 years, salesperson A has earned twice as much as salesper B who in turn has averaged 50% more than salesper C. T
bekas [8.4K]
<span>A has earned twice as much as B so: A=2B
B has averaged 50% more than C so: B=C+0.5C
Combined is 220K, So A+B+C=220,000

The last equation can be re-written as:
2B+1.5C+C=220K
AND since A=2B, it can be rewritten again as:
3C+1.5C+C=220K

Now you can get C finally, since B=1.5C you can get B, then to get the average, just divide that by 3 (years) and you should be done.
So B = 60000 for 3 years</span>
4 0
3 years ago
Read 2 more answers
Please help with the question in the picture!
Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

<u>METHOD - I</u>

<u><em>Sin² C + Cos² C = 1</em></u>

Cos² C = 1 - Sin² C

Cos² C = 1 - \frac{9}{25}

Cos² C = \frac{25 - 9}{25}

Cos² C = \frac{16}{25}

Cos C = \sqrt{\frac{16}{25} }

Cos C = \frac{4}{5}

As we know that

Tan C = \frac{Sin C}{Cos C }

<em>Tan C = \frac{\frac{3}{5} }{\frac{4}{5} }</em>

<em>Tan C = \frac{3}{4}</em>

<u>METHOD - II</u>

Given Sin C = \frac{3}{5} = \frac{Height}{Hypotenuse}

therefore,  

AB ( Height ) = 3; BC ( Hypotenuse) = 5

<em>∵ ΔABC is Right triangle.</em>

<em>∴ By Pythagorean Theorem-</em>

<em>AB² + AC² = BC²</em>

<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>

<em>AC² = 5² - 3²</em>

<em>AC² = 25 - 9</em>

<em>AC² = 16</em>

<em>AC  ( Base) = 4</em>

<em>Since, </em>

<em>Tan C = \frac{Height}{Base}</em>

<em>Tan C = \frac{AB}{AC}</em>

<em>Hence Tan C = \frac{3}{4}</em>

<em />

4 0
3 years ago
Evaluate tan(Sin-1(-5/13)). Answer as a fraction please.
dangina [55]

Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))

Let A = arcsin(-5/13) = -arcsin(5/13)

Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0
3 years ago
Helllpppppppppp please someone.?????
Liula [17]

Answer:

(-5,5)

Step-by-step explanation:

Multiply the first equation by -2,and multiply the second equation by 1.

−2(x+5y=20)

1(2x−7y=−45)

Becomes:

−2x−10y=−40

2x−7y=−45

Add these equations to eliminate x:

−17y=−85

Then solve−17y=−85for y:

(Divide both sides by -17)

y=5

x+5y=20

Substitute  5 for y in x+5y=20:

x+(5)(5)=20

x+25=20(Simplify both sides of the equation)

x+25+−25=20+−25(Add -25 to both sides)

x=-5

6 0
2 years ago
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