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qaws [65]
3 years ago
8

A 1000 kg train car traveling at 12 m/s on a level track has 400 kg of sand dumped, vertically, into it. What is the final speed

of the train car after the sand is dumped into it? Ignore friction
Physics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

The final speed of the train car is 8.57 m/s.

Explanation:

Given that,

Mass of train car = 1000 kg

Mass of sand = 400 kg

Speed of train car = 12 m/s

We need to calculate the final speed of the train car after the sand is dumped

Using conservation of momentum

m_{1}u_{1}=(m_{1}+m_{2})v...(I)

Put the value in the equation (I)

1000\times12=(1000+400)v

v=\dfrac{1000\times12}{1400}

v=8.57\ m/s

Hence, The final speed of the train car is 8.57 m/s.

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A monument has a height of 348 ft, 8 in. Express this height in meters. Answer in units of m.
tensa zangetsu [6.8K]

Answer:

The height of mountain in meter will be 106.2732 m

Explanation:

We have given height of mountain = 348 ft,8 in

We know that 1 feet = 0.3048 meter

So 348 feet =348\times 0.3048=106.07meter

And we know that 1 inch = 0.0254 meter

So 8 inch 8\times 0.0254=0.2032m

So the total height of mountain in meter = 106.07+0.2032 = 106.2732 m

The height of mountain in meter will be 106.2732 m

4 0
3 years ago
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Explanation:

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Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.
melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

                 P.E_{1} = mgz_{1}

       P.E_{1} = (\rho V)gz_{1}    

                    = 1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m

                    = 1164000 J

or,                = 1164 kJ         (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

             \Delta P.E = mg(z_{2} - z_{1})

                         = \rho \times V \times g (z_{2} - z_{1})

                         = 1000 \times 3 \times 9.7 (10 - 40)m

                         = -873000 J

or,                      = -873 kJ

Thus, we can conclude that change in  gravitational potential energy is -873 kJ.

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two ends of an inextensible string of length 12m are attached to points Aand B 1.2m apart,in the same horizontal plane.a mass 20
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Flauer [41]

Answer:

I just toughed it out and talked with friends

Explanation:

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