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dem82 [27]
3 years ago
11

Two balloons (m = 0.012 kg) are separated by a distance of d = 15 m. They are released from rest and observed to have an instant

aneous acceleration of a = 1.9 m/s2 toward each other at the moment they are released. Assume the two balloons are point charges and have equal but opposite charges.
Physics
1 answer:
Evgesh-ka [11]3 years ago
3 0

Answer:

1.492*10^14 electrons

Explanation:

Since we know the mass of each balloon and the acceleration, let’s use the following equation to determine the total force of attraction for each balloon.

F = m * a = 0.012 * 1.9 = 0.0228 N

Gravitational forces are negligible

Charge force = 9 * 10^9 * q * q ÷ 225

= 9 * 10^9 * q^2 ÷ 225 = 0.0228

q^2 = 5.13 ÷ 9 * 10^9

q = 2.387 *10^-5

This is approximately 2.387 *10^-5 coulomb of charge. The charge of one electron is 1.6 * 10^-19 C

To determine the number of electrons, divide the charge by this number.

N =2.387 *10^-5  ÷ 1.6 * 10^-19 = 1.492*10^14 electrons

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Answer:

Will be doubled.

Explanation:

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Now we can isolate V, the potential difference between the plates as:

V = \frac{Q}{e_0} *\frac{d}{A}

Now, notice that the separation between the plates is in the numerator.

Thus, if we double the distance we will get a new potential difference V', such that:

V' = \frac{Q}{e_0} *\frac{2d}{A} = 2*( \frac{Q}{e_0} *\frac{d}{A}) = 2*V\\V' = 2*V

So, if we double the distance between the plates, the potential difference will also be doubled.

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3 years ago
Describe how Newton’s third law applies to the box and the table.
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the box has vertical force on the table

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After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average
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