Answer:
It is centripetal force i think hope it helps:)
Explanation:
Answer:
Stringed instruments (chordophones).
Explanation:
Musical instruments that produce sound by vibration of a stretched string are called stringed instruments (chordophones).
Some examples of stringed instruments are guitar, piano, harp, violin, sitar etc.
A guitar can be defined as a musical instrument with six or twelve strings and a long fretted fingerboard that are being played using a plectrum or by strumming (plucking) with the fingers, usually in a downward direction.
Basically, a guitar is a musical instrument that produces sound through regular vibrations and as a result of this, it is used for creating uniform and melodious sounds.
Answer:
A balloon is floating up into the air at 1 m/s.
Explanation:
Velocity is the displacement divided by the time;
Velocity =
It is a vector quantity that has magnitude and direction.
The choice that shows a change in direction is a correct specification of velocity.
A balloon floating up into the air at 1m/s shows no directional change.
(a) Let's convert the final speed of the car in m/s:
![v_f = 61 km/h = 16.9 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2061%20km%2Fh%20%3D%2016.9%20m%2Fs)
The kinetic energy of the car at t=19 s is
![K= \frac{1}{2}mv_f^2= \frac{1}{2}(1400 kg)(16.9 m/s)^2=2.00 \cdot 10^5 J](https://tex.z-dn.net/?f=K%3D%20%5Cfrac%7B1%7D%7B2%7Dmv_f%5E2%3D%20%5Cfrac%7B1%7D%7B2%7D%281400%20kg%29%2816.9%20m%2Fs%29%5E2%3D2.00%20%5Ccdot%2010%5E5%20J%20%20)
(b) The average power delivered by the engine of the car during the 19 s is equal to the work done by the engine divided by the time interval:
![P= \frac{W}{\Delta t}](https://tex.z-dn.net/?f=P%3D%20%5Cfrac%7BW%7D%7B%5CDelta%20t%7D%20)
But the work done is equal to the increase in kinetic energy of the car, and since its initial kinetic energy is zero (because the car starts from rest), this translates into
![P= \frac{K}{\Delta t}= \frac{2.00 \cdot 10^5 J}{19 s}=1.05 \cdot 10^4 W](https://tex.z-dn.net/?f=P%3D%20%5Cfrac%7BK%7D%7B%5CDelta%20t%7D%3D%20%5Cfrac%7B2.00%20%5Ccdot%2010%5E5%20J%7D%7B19%20s%7D%3D1.05%20%5Ccdot%2010%5E4%20W%20%20)
(c) The instantaneous power is given by
![P_i = Fv_f](https://tex.z-dn.net/?f=P_i%20%3D%20Fv_f)
where F is the force exerted by the engine, equal to F=ma.
So we need to find the acceleration first:
![a= \frac{v_f-v_i}{\Delta t}= \frac{16.9 m/s}{19 s}=0.89 m/s^2](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv_f-v_i%7D%7B%5CDelta%20t%7D%3D%20%20%5Cfrac%7B16.9%20m%2Fs%7D%7B19%20s%7D%3D0.89%20m%2Fs%5E2%20)
And the problem says this acceleration is constant during the motion, so now we can calculate the instantaneous power at t=19 s:
Answer:
The long, light-colored lines extending from many craters on the Moon are called rays and are "crater rays".
Explanation:
Hope this helps :)
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