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sashaice [31]
3 years ago
15

Solve each given equation and show your work. Tell whether it has one solution, an infinite number of solutions, or no solutions

, and identify each equation as an identity, a contradiction, or neither.
A) 6X plus 4X -6 = 24+ 9X

B) 25 - 4X = 15 - 3X +10 - X

C) 4X +8 = 2X +7+ 2X -20

Mathematics
1 answer:
Natali [406]3 years ago
4 0
I hope this helps you

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Which products result in a difference of squares? Check all that apply.(x – y)(y – x)(6 – y)(6 – y)(3 + xz)(–3 + xz)(y2 – xy)(y2
nikitadnepr [17]

1. (3 + xz)(–3 + xz)

2. (y² – xy)(y² + xy)

3. (64y2 + x2)(–x2 + 64y2)

Explanation

The difference of 2 squares is in the form (a+b)(a-c).

(3 + xz)(–3 + xz) = (3 + xz)(xz -3)

                           = (xz + 3)(xz - 3)

                          = x²y²-3xy+3xy-9

                          =x²y² - 3²

(y² – xy)(y² + xy) = y⁴+xy³-xy³-x²y²

                          = y⁴ - x²y²

(64y2 + x2)(–x2 + 64y2)= (64y²+x²)(64y²-x²)

                                      = 4096y⁴-64y²x²+64y²x²-x⁴

                                      = 4096y⁴ - x⁴

3 0
3 years ago
In an arithmetic sequence, if a2= 5 and a10= 19 find a6
OLEGan [10]

Answer:

a₆ = 12

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₂ = 5 and a₁₀ = 19 , then

a₁ + d = 5 → (1)

a₁ + 9d = 19 → (2)

Subtract (1) from (2) term by term to eliminate a₁

8d = 14 ( divide both sides by 8 )

d = 1.75

Substitute d = 1.75 into (1)

a₁ + 1.75 = 5 ( subtract 1.75 from both sides )

a₁ = 3.25

Then

a₆ = 3.25 + 5(1.75) = 3.25 + 8.75 = 12

6 0
3 years ago
Which situation could be represented by the graph shown?
Llana [10]
I think it’s 30 not gonna lie I’m gonna get somebody



Let’s see if there’s anyone!!!!!!!!!!!!

A.
7 0
3 years ago
What is the length of the actual dining room?
Schach [20]
120 inches.

This is because to find the scale factor, you have to take the square root of the area scale. This will give you 30-1 ratio. Then multiply the 4 by that number. 
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3 years ago
Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:
Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side  that is  ().

Therefore the required interval form is

[-6,-2)U(-2,3)

As we see that () are used with -2 and 3 . And that's the required interval form .

5 0
3 years ago
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