1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
weeeeeb [17]
3 years ago
6

Pls help i need help with this been working fo a bit

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0

\\ \sf\Rrightarrow \dfrac{6}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}(y+x)

\\ \sf\Rrightarrow \dfrac{6}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}x+\dfrac{5}{7}y

\\ \sf\Rrightarrow \dfrac{6}{7}x+\dfrac{5}{7}x-\dfrac{2}{5}y+\dfrac{5}{7}y

\\ \sf\Rrightarrow \dfrac{11}{7}x+\dfrac{-14+25}{35}y

\\ \sf\Rrightarrow \dfrac{11}{7}x+\dfrac{11}{35}y

Done!

larisa [96]3 years ago
6 0

\boxed{\huge \bf  \: Question:—}

\sf \longmapsto \:  \dfrac{6}{7} x -   \dfrac{2}{5}  y  +  \dfrac{5}{7} (y + x)

\boxed{\huge\bf \: Solution:—}

\boxed{\bf \: Distribute:—}

\sf \longmapsto \:  \dfrac{6}{7} x -   \dfrac{2}{5}  y  +  \dfrac{5}{7} y +  \dfrac{5}{7}  \: x

\sf \longmapsto \dfrac{6}{7} x +  \dfrac{ - 2}{5} y +  \dfrac{5}{7} y \:  +  \dfrac{5}{7} x

\boxed{\bf \: Combining  \: Like  \: Terms:—}

\sf \longmapsto\dfrac{6}{7} x +  \dfrac{ - 2}{5} y +  \dfrac{5}{7} y \:  +  \dfrac{5}{7} x

\sf \longmapsto  \bigg(\dfrac{6}{7} x +  \dfrac{5}{7} x \bigg) \:  +  \bigg( \dfrac{ - 2}{5} y  +  \dfrac{5}{7}  \: y \bigg)

\sf \longmapsto \:  \dfrac{11}{7}  x \:  +  \dfrac{11}{35} y

\boxed{\bf \: Answer:—}

\boxed{\bf \: \dfrac{11}{7}  x \:  +  \dfrac{11}{35} y}

You might be interested in
Three students, Alicia, Benjamin, and Caleb, are constructing a square inscribed in a circle with center at point C. Alicia draw
True [87]

Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

<h3>Inscribing a square</h3>

The steps involved in inscribing a square in a circle include;

  • A diameter of the circle is drawn.
  • A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
  • The resulting four points on the circle are the vertices of the inscribed square.

Alicia deductions were;

Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle

Benjamin's deductions;

The diameters must be perpendicular to each other. Then connect the points, in order, around the circle

Caleb's deduction;

No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.

It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.

Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.

Learn more about an inscribed square here:

brainly.com/question/2458205

#SPJ1

6 0
2 years ago
Tramserran? Do you think you could lend a hand for these questions? You have saved my life on more than one occasion. It's Algeb
Makovka662 [10]

Answer:

#1). 6 , 18 , 54

#2). 5/3 , 14 / 9 , 41/27

#3). 1.5 , 2.5 , 2.5

Step-by-step explanation:

#1).

g(x) = 3x

g(2) = 3 . 2 = 6

g²(2) = 3 . 3 . 2 = 18

g³(2) = 3 . 3 . 3 . 2 = 54

#2).

g(x) = 1/3 x + 1

g(2) = 2/3 + 1 = 5/3

g²(2) = g(5/3) = 5/9 + 1 = 14/9

g³(2) = g(14/9) = 14/27 + 1 = 41/27

#3).

g(x) = -1 ║x - 2 ║ + 3

g(0.5) = -1 (1.5) + 3 = 1.5

g²(0.5) = g(1.5) = -1(0.5) + 3 = 2.5

g³(0.5) = g(2.5) = -1(0.5) + 3 = 2.5

8 0
3 years ago
Read 2 more answers
Help Please!<br>parallel and perpendicular lines
e-lub [12.9K]
For what problem
Answer pls
5 0
3 years ago
Read 2 more answers
Round to nearest hundredth<br>0.099​
Degger [83]

Answer: 0.10

Step-by-step explanation:

Find the number in the hundredth place

9

9

and look one place to the right for the rounding digit

9

9

. Round up if this number is greater than or equal to

5

5

and round down if it is less than

5

5

.

0.10

8 0
3 years ago
Decompose the figure into regions that are closest to each
Korolek [52]

The image is decomposed as follows: H1 and H2. Where original graph is Hx.

<h3>Are the images (attached) valid decompositions of the original graph?</h3>

  • Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
  • H1 ∪ H2 = Hx
  • They have no edges in common.

Hence, {H1 , H2} are valid decomposition of G.

<h3>What is a Graph Decomposition?</h3>

A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx

See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.

Learn more about decomposition:
brainly.com/question/27883280
#SPJ1

7 0
1 year ago
Other questions:
  • Which pair of figures has the same number of faces as vertices?
    5·2 answers
  • Is true or false 18= 18.00​
    9·1 answer
  • 47 x 10^6 x 78 x 10^-3 in scientific notation
    6·1 answer
  • Could someone answer this for me?​
    11·1 answer
  • DUE TODAY HELP
    15·1 answer
  • Can someone help me please I am losing my mind
    6·1 answer
  • Find the slope of a line that passes through the following points (3,2) (5,-3)
    7·1 answer
  • Solve the system of linear equations using any method you choose:<br> -6x + 3y = 18<br> 10x - y = 4
    11·1 answer
  • Five hundred and two ten thousandths as a decimal ​
    5·1 answer
  • The table gives information about the speeds, in kilometres per hour, of 80 motorbikes as each pass under a bridge.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!