Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
<h3>
Inscribing a square</h3>
The steps involved in inscribing a square in a circle include;
- A diameter of the circle is drawn.
- A perpendicular bisector of the diameter is drawn using the method described as the perpendicular of the line sector. Also known as the diameter of the circle.
- The resulting four points on the circle are the vertices of the inscribed square.
Alicia deductions were;
Draws two diameters and connects the points where the diameters intersect the circle, in order, around the circle
Benjamin's deductions;
The diameters must be perpendicular to each other. Then connect the points, in order, around the circle
Caleb's deduction;
No need to draw the second diameter. A triangle when inscribed in a semicircle is a right triangle, forms semicircles, one in each semicircle. Together the two triangles will make a square.
It can be concluded from their different postulations that Benjamin is correct because the diameter must be perpendicular to each other and the points connected around the circle to form a square.
Thus, Benjamin is correct about the diameter being perpendicular to each other and the points connected around the circle.
Learn more about an inscribed square here:
brainly.com/question/2458205
#SPJ1
Answer:
#1). 6 , 18 , 54
#2). 5/3 , 14 / 9 , 41/27
#3). 1.5 , 2.5 , 2.5
Step-by-step explanation:
#1).
g(x) = 3x
g(2) = 3 . 2 = 6
g²(2) = 3 . 3 . 2 = 18
g³(2) = 3 . 3 . 3 . 2 = 54
#2).
g(x) = 1/3 x + 1
g(2) = 2/3 + 1 = 5/3
g²(2) = g(5/3) = 5/9 + 1 = 14/9
g³(2) = g(14/9) = 14/27 + 1 = 41/27
#3).
g(x) = -1 ║x - 2 ║ + 3
g(0.5) = -1 (1.5) + 3 = 1.5
g²(0.5) = g(1.5) = -1(0.5) + 3 = 2.5
g³(0.5) = g(2.5) = -1(0.5) + 3 = 2.5
For what problem
Answer pls
Answer: 0.10
Step-by-step explanation:
Find the number in the hundredth place
9
9
and look one place to the right for the rounding digit
9
9
. Round up if this number is greater than or equal to
5
5
and round down if it is less than
5
5
.
0.10
The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
brainly.com/question/27883280
#SPJ1