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alexandr402 [8]
4 years ago
11

A cheerleader is being held 4 feet off the ground. She is tossed into the air with an initial speed of 32 feet per second. Her h

eight t seconds after she is thrown can be estimated by 4+32t-16tsecondpower. About how high is the cheerleader 2 seconds after she is tossed?
Mathematics
1 answer:
pentagon [3]4 years ago
3 0
The cheerleader is already 4 feet above the ground to start with
if she's being tossed at 32 feet per second and you want her height after 2 seconds, you just multiply 32 by 2=64 feet
64 feet + the initial 4 feet = 68 feet
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Answer:

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Step-by-step explanation:

Given the following

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Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

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Answer:

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Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

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Given:

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t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

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Compute the 80% confidence interval for difference between two means as follows:

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