A cheerleader is being held 4 feet off the ground. She is tossed into the air with an initial speed of 32 feet per second. Her h

Question

4 years ago

11

A cheerleader is being held 4 feet off the ground. She is tossed into the air with an initial speed of 32 feet per second. Her h

eight t seconds after she is thrown can be estimated by 4+32t-16tsecondpower. About how high is the cheerleader 2 seconds after she is tossed?

Mathematics

1 answer:

pentagon [3] · Answer 1 · 2021-11-04T01:41:00+03:00

pentagon [3]4 years ago

3 0

The cheerleader is already 4 feet above the ground to start with
if she's being tossed at 32 feet per second and you want her height after 2 seconds, you just multiply 32 by 2=64 feet
64 feet + the initial 4 feet = 68 feet