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alexandr402 [8]
4 years ago
11

A cheerleader is being held 4 feet off the ground. She is tossed into the air with an initial speed of 32 feet per second. Her h

eight t seconds after she is thrown can be estimated by 4+32t-16tsecondpower. About how high is the cheerleader 2 seconds after she is tossed?
Mathematics
1 answer:
pentagon [3]4 years ago
3 0
The cheerleader is already 4 feet above the ground to start with
if she's being tossed at 32 feet per second and you want her height after 2 seconds, you just multiply 32 by 2=64 feet
64 feet + the initial 4 feet = 68 feet
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fredd [130]

Answer:

(- 4, - 10 )

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Help needed math 3 - 10 points read closely
inessss [21]
<h2>Hello!</h2>

The answer is:

The answer is the fourth option,

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<h2>Why?</h2>

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\left \{ {{\frac{1}{x}, if x

There, we know that:

We should use the first expression if the value to evaluate is less than -2.

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We should use the second expression if the value to evaluate is greater or equal than 2.

So, for this case, the function will be:

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Have a nice day!

7 0
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MakcuM [25]

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