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Otrada [13]
2 years ago
14

How many times larger is 3 x 10 to the power of negative 5 end exponent than 6 x 10 to the power of negative 12 end exponent

Mathematics
1 answer:
valentinak56 [21]2 years ago
6 0
For you to be able to answer this you might need a tall numberline
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(Will Mark Brainliest!!!)Choose the point-slope form of the equation below that represents the line that passes through the poin
krek1111 [17]

Answer:

b

Step-by-step explanation:

the point-slope form of the equation is equal to

6 0
3 years ago
What values for theta (0 less than or equal to theta less than equal to 2pi) satisfy the equation?
Novosadov [1.4K]
Solve this as you would an equation that does not involve trig.  Don't let the trig scare you.  If you had to solve 2x+8=0, the first thing you would do is factor out the common 2.  In our equation, we have a common cos theta.  I'm going to use beta as my angle.  When we factor out beta, here's what we have. cos \beta (2sin \beta +1)=0.  The Zero Product Property tells us that at least one of those factors has to equal zero.  So we set them both equal to zero and solve.  Let's get the equations first, then we will need our unit circle.  First equation set to equal zero is cos \beta =0.  On our unit circle, cos is the value inside the parenthesis that is in the x position within our coordinate.  Look at all those coordinates as you go around the unit circle once (once around is equivalent to 2pi).  You will find that the the cos is 0 at \frac{ \pi }{2}, \frac{3 \pi }{2}.  The next equation is 2sin\beta +1=0.  Move the 1 over by subtraction and divide by 2 to get sin \beta =- \frac{1}{2}.  Same as before, go around the unit circle one time and look to see where the coordinate in the y place is -1/2.  Sin corresponds to the y coordinate.  You will find that sin is -1/2 at \frac{7 \pi }{6}, \frac{11 \pi }{6}.  And there you go!  Trig is so much fun!!!
7 0
3 years ago
If the ratio y/x is the same for all related pairs of x and y, what does that mean
Verizon [17]

Answer:

The same ratio indicates that there is a proportional relationship between y and x.

Step-by-step explanation:

We know when y varies directly with x, the equation is

y ∝ x

y=kx

k\:=\:\frac{y}{x}

Here,

k is the constant of proportionality.

The ratio y/x indicates that k is a constant of proportionality.

Thus, the same ratio indicates that there is a proportional relationship between y and x.

When x increases, y increases, and when y decreases, x also decreases.

4 0
2 years ago
Farmer Ed has 8,000 meters of fencing & wants to enclose a rectangular plot that borders a river. If farmer Ed does not fenc
Elina [12.6K]

Answer:

largest area that can be enclosed = 8,000,000 m²

Step-by-step explanation:

Since it is a rectangle plot, the area is expressed as; A = xy, where x is length and y is width.

Because it is next to the river, he only needs to fence three sides, so amount of fencing; F = x + 2y.

Since we know the amount of fencing available is 8000m, we get:

8000 = x + 2y

solving for x, we have;

x = 8000 - 2y

substitute 8000 - 2y for x into the area equation to give;

A = (8000 - 2y)y distribute

A = -2y² + 8000y

Now, due to the negative sign next to 2, this will be a parabola which opens down, meaning that the point of maximum area will be at the vertex,

Thus; y = -b/2a = -8000/[2(-2)] = 2000

x = 8000 - 2(2000) = 4000

A = 4000(2000) = 8,000,000 m²

7 0
3 years ago
Is x^2 + 1/x = 4 a quadratic equations​
Liono4ka [1.6K]

Answer:

\large\boxed{\pink{ \leadsto The \ given \ equation \ is \ not \ a \ Quadratic \ equation . }}

Step-by-step explanation:

Given equation to us is ,

\green{\implies x^2+\dfrac{1}{x}=4 }

So , a equation is said to be a quadratic equation if the highest degree of the variable is 2 . On simplifying the Equation ,

\implies x^2 +\dfrac{1}{x}=4

Taking x as LCM ,

\implies \dfrac{x^2.x + 1 }{x}= 4

Transposing x to RHS .

\implies x^3 + 1 = 4x

Putting all terms in LHS

\boxed{\bf \implies x^3 - 4x - 1 = 0 }

Since here the highest degree of the variable is 3 not 2 . So its a cubic equation and not a quadratic equation .

<h3><u>Hence</u><u> </u><u>the </u><u>given </u><u>equation </u><u>is</u><u> </u><u>not</u><u> </u><u>a</u><u> </u><u>quad</u><u>ratic</u><u> equation</u><u> </u><u>.</u></h3>
4 0
2 years ago
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