Nina's garden 4 1/5 meters long and 3/10 meter wide. What is the area of Nina's garden?

Mathematics

1 answer:

taurus [48]3 years ago

3 0

Answer:

63/50 as an improper fraction.

1 13/50 as a mixed number

Step-by-step explanation:

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In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.

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Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2

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3 years ago

Nina's garden 4 1/5 meters long and 3/10 meter wide. What is the area of Nina's garden?​

Nina's garden 4 1/5 meters long and 3/10 meter wide. What is the area of Nina's garden?