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2 years ago

What is the rectangle's height and base?

Mathematics

2 answers:

HACTEHA [7]2 years ago

6 0

Answer:

Base = 16cm

Height = 7cm

riadik2000 [5.3K]2 years ago

3 0

Answer:

base = 16 cm

height = 7 cm

Step-by-step explanation:

area of a rectangle = base (b) x height (h)

base (b) = 9 + h

area = 112 cm²

plug in values:

112 = (9 + h) * h

112 = 9h + h²

h² + 9h - 112 = 0

<u>h can be solved using quadratic equation</u>

-9 ± √ (9² - 4 (1) (-112))

h = --------------------------------------

-9 ± √529

h = ----------------

h = 7 ; h = -16

therefore the height of a rectangle (h) = 7 cm

<u>solve for base (b)</u>

base (b) = 9 + h

base (b) = 9 + 7

base (b) = 16 cm

proof:

area of a rectangle = base (b) x height (h)

112 = 16 * 7

112 = 112 ---- ok

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Liula [17]

This question is solved applying the formula of the area of the rectangle, and finding it's width. To do this, we solve a quadratic equation, and we get that the cardboard has a width of 1.5 feet.

Area of a rectangle:

The area of rectangle of length l and width w is given by:

$A = wl$

w(2w + 3) = 9

From this, we get that:

$l = 2w + 3, A = 9$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

In this question:

$w(2w+3) = 9$

$2w^2 + 3w - 9 = 0$

Thus a quadratic equation with $a = 2, b = 3, c = -9$

Then

$\Delta = 3^2 - 4(2)(-9) = 81$

$w_{1} = \frac{-3 + \sqrt{81}}{2*2} = 1.5$

$w_{2} = \frac{-3 - \sqrt{81}}{2*2} = -3$

Width is a positive measure, thus, the width of the cardboard is of 1.5 feet.

Another similar problem can be found at brainly.com/question/16995958

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