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hoa [83]
3 years ago
6

What is the rectangle's height and base?

Mathematics
2 answers:
HACTEHA [7]3 years ago
6 0

Answer:

Base = 16cm

Height = 7cm

riadik2000 [5.3K]3 years ago
3 0

Answer:

base = 16 cm

height = 7 cm

Step-by-step explanation:

area of a rectangle = base (b) x height (h)

base (b) = 9 + h

area = 112 cm²

plug in values:

112 = (9 + h) * h

112 = 9h + h²

h² + 9h - 112 = 0

<u>h can be solved using quadratic equation</u>

       -9 ± √ (9² - 4 (1) (-112))

h = --------------------------------------

                        2

     -9 ± √529

h = ----------------

            2

h = 7  ;    h = -16

therefore  the height of  a rectangle (h) = 7 cm

<u>solve for base (b)</u>

base (b) = 9 + h

base (b) = 9 + 7

base (b) = 16 cm

proof:

area of a rectangle = base (b) x height (h)

112 = 16 * 7

112 = 112 ---- ok

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I hope I helped you^_^

7 0
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Solve the following equation. Round solution to the tenths place.<br> 29 = с/7.2<br> C =
expeople1 [14]

Answer:

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Step-by-step explanation:

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What is -15xy + 25x factored
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Since -5x is common to both factors, hence the factored form is;

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melamori03 [73]

Answer:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

Data given: 114 157 203 257 284 299 305 344 378 410 421 450 478 480 512 533 545

The confidence interval for the population variance \sigma^2 is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^{17} (x_i -\bar x)^2}{n-1}}

And in order to find the sample mean we just need to use this formula:

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The sample mean obtained on this case is \bar x= 362.941 and the deviation s=132.250

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

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The excel commands would be: "=CHISQ.INV(0.05,16)" "=CHISQ.INV(0.95,16)". so for this case the critical values are:

\chi^2_{\alpha/2}=26.296

\chi^2_{1- \alpha/2}=7.962

And replacing into the formula for the interval we got:

\frac{(16)(132.250)^2}{26.296} \leq \sigma \leq \frac{(16)(132.250)^2}{7.962}

10641.959 \leq \sigma^2 \leq 35147.074

Now we just take square root on both sides of the interval and we got:

103.160 \leq \sigma \leq 187.476

And the upper bound rounded to the nearest integer would be 187.

4 0
3 years ago
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