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3 years ago

What is 13/20 written as a decimal?

Mathematics

1 answer:

leonid [27]3 years ago

6 0

To find decimals out of fractions, you divide 13 and 20, which equals 0.65.

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Find y when x=9 if y varies directly as x, and y=245 when x=7

Aleonysh [2.5K]

Since y varies directly as x, you know that y=245 and x=7 can be used as a proportion, 245/7. When you multiply this proportion to 9, you get 315. This is the value of y when x=9.

y=315

8 0

3 years ago

< Triangle HIJ is rotated 90 degrees about the origin and dilated by a scale o factor of 2 (with respect to the origin). What

Naddik [55]

Upload a picture of the graph.

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3 years ago

Marianna [84]

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Step-by-step explanation:

Let us revise some logarithmic rules

$log(a)^{n}=nlog(a)$
$log(ab)=log(a)+log(b)$
$nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]$

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴ 10 log(x) = $log(x)^{10}$

- Then re-write 5 log(64)

∴ 5 log(64) = $log(64)^{5}$

∴ 10 log(x) + 5 log(64) = $log(x)^{10}$ + $log(64)^{5}$

- Use the 3rd rule above to make it single logarithm

∵ $log(x)^{10}$ + $log(64)^{5}$ = $log[(x)^{10}][(64)^{5}]$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(64)^{5}]$

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as $2^{6}$

∴ $(64)^{5}=(2^{6})^{5}$

- Multiply the two powers of 2

∴ $(64)^{5}=(2)^{30}$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(2)^{30}]$

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0

3 years ago

URGENT! 20 POINTS

Nonamiya [84]

Answer:

128; 137

Step-by-step explanation:

Plug the arm span into the formula

5 0

4 years ago

Petrolyn motor oil is a combination of natural oil and synthetic oil. It contains 8 liters of natural oil for every 5 liters of

coldgirl [10]

Answer:

it would need 40 liters of natural oil

8x5=40

5 0

3 years ago