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-BARSIC- [3]
2 years ago
12

To move the first line of text over five spaces and leave the other lines of the paragraph aligned to the left, use the _____ fe

ature. hanging indent first-line indent justify line-spacing
Computers and Technology
2 answers:
Sergeeva-Olga [200]2 years ago
6 0

the answer i think is (B


Lera25 [3.4K]2 years ago
4 0

To move the first line of text over five spaces and leave the other lines of the paragraph aligned to the left, use the FIRST LINE INDENT.

<h2>Your answer would be B. First Line Indent</h2><h3><u><em>hope this helps</em></u></h3>
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An ipv4 address in the range 169.254.0.1 through 169.254.255.254 indicates a problem with what type of service
DENIUS [597]

Dynamic Host Configuration Protocol, also known as DHCP.

3 0
2 years ago
1. How many bits would you need to address a 2M × 32 memory if:
Dominik [7]

Answer:

  1. a) 23       b) 21
  2. a) 43        b) 42
  3. a) 0          b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8;  L = ( 2M * 32 ) / 8 =  2M * 4

hence number of bits =  log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 ,  item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0
2 years ago
Write a Python program to convert the characters to lowercase in a string
wel

Answer:

Following is the program in the python language

st = 'sAN RaN'  #String

print(st.lower()) #display into the lowercase

Output:

san ran

Explanation:

Following are the description of program

  • Declared and initialized the string in the "st" variable .
  • The lower function in python is used for converting the uppercase string into the lower case string .
  • Finally in the print function we used lower function and display the  string into the lower case
8 0
3 years ago
There are numerous strict and steadfast rules when it comes to composition.
erastova [34]

Answer:

false

Explanation:

none ¯\_(ツ)_/¯

6 0
2 years ago
Will give brainliest and good amount of points, no false answers.
nlexa [21]

The problem with the swap function is that it loses the value at the first index, as soon as it gets overwritten by the value at the second index. This happens in the first statement. To fix it, you need a helper variable.

First you're going to "park" the index at the first index in that helper variable, then you can safely overwrite it with the value at the second index. Then finally you can write the parked value to the second index:

var swap = function(array, firstIndex, secondIndex) {

let helper = array[firstIndex];

array[firstIndex]  = array[secondIndex];

array[secondIndex] = helper;

};

I hope this makes sense to you.

7 0
3 years ago
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