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Elden [556K]
3 years ago
13

The number 16 in carbon-16 stands for carbons

Chemistry
1 answer:
Oksanka [162]3 years ago
5 0

Answer:

nice info

paragraph

lolololololo

Explanation:

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Calculate the specific heat in calories per °C of a 2.00 lb pure iron bar.<br> Plz help me!!!
nekit [7.7K]

Answer:

402.7897

Explanation:

Pretty sure but not 100% about it.

grams in 2 pounds = 907.184 * specific heat of iron = .444

=402.789696

4 0
2 years ago
Explain how the crystals of an igneous rock are used to help classify it?
Hatshy [7]
Classify what. explain more
6 0
3 years ago
Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?
Molodets [167]
It wont melt like gold and copper would at that temperature

4 0
3 years ago
Read 2 more answers
Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
A car with a mass of 1,100 kg is moving with a velocity of 30 m/s due east . What is the moment?
dexar [7]
Momentum = (mass) x (velocity) = (1,100) x (30) =

33,000

kg-m/sec due east

6 0
2 years ago
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