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Mazyrski [523]
2 years ago
14

How many moles of copper are there in 6.93 g of copper samplepls be quick​

Chemistry
2 answers:
aniked [119]2 years ago
8 0

Answer:

Hope it will help you a lot.

Alex_Xolod [135]2 years ago
7 0
  • Molar mass of copper=63.5g/mol
  • Given mass=6.93g

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}

\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles

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Someone please help i don’t have much time left
REY [17]

Answer: Energy of reactants = 30, Energy of products = 10

Exothermic

Activation energy for forward reaction is 10.

Explanation:

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Energy of reactants = 30

Energy of products = 10

Thus as energy of the product < energy of the reactant, the reaction is exothermic.

Activation energy (E_a) is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

E_a for forward reaction is (40-30) = 10.

6 0
3 years ago
For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

6 0
3 years ago
Noah and Nina are 15 m apart in a closed room. Noah says the same sentence twice. The first time, Nina does not hear the sound,
In-s [12.5K]

The air molecules in the compressions of the second wave are denser, so the sound is louder.

<h3>What is a sound wave?</h3>

Sound waves are longitudinal waves that travel through a medium like air or water.

In a closed room, Noah and Nina are sitting 15 m apart.

As Noah says the same sentence twice, Nina does not hear the sound the first time but she does hear the sentence the second time.

This happens as the air molecules in the compressions of the second wave are denser. As a result, the sound is louder.

The correct option is ''The air molecules in the compressions of the second wave are denser, so the sound is louder''.

Learn more about the sound wave here:

brainly.com/question/1554319

#SPJ1

5 0
1 year ago
If 30 grams of KCl is dissolved at 10°C, how many additional grams would be needed to make the solution saturated at 60°C? * Cap
MariettaO [177]

If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

<h3>What is a saturated solution?</h3>

A saturated solution is a solution in which there is so much solute that if there was any more, it would not dissolve. Its concentration is the same as the solubility at that temperature.

  • Step 1. Calculate the mass of water.

At 10 °C, the solubility is 31.2 g KCl/100 g H₂O.

30 g KCl × 100 g H₂O/31.2 g KCl = 96 g H₂O

  • Step 2. Calculate the mass of KCl required to prepare a saturated solution at 60 °C.

At 60 °C, the solubility is 45.8 g KCl/100 g H₂O.

96 g H₂O × 45.8 g KCl/100 g H₂O = 44 g KCl

  • Step 3. Calculate the mass of KCl that must be added.

44 g - 30 g = 14 g

If 30 grams of KCl is dissolved at 10°C, 14 g of KCl should be added to make a saturated solution at 60 °C.

Learn more about saturated solutions here: brainly.com/question/24564260

6 0
2 years ago
If the equilibrium concentrations of products are much greater than those of reactants in this system, what would be the magnitu
miss Akunina [59]

Answer:

K > 1.

Explanation:

∵ The equilibrium constant K = [products]/[reactants].

Since, [products] > [reactants].

<em>∴ The equilibrium constant K > 1.</em>

5 0
3 years ago
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