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babymother [125]
2 years ago
15

Help me please:(:(:( with my bellwork for brainiest

Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
3 0

Answer:

Elements are made of only one kind of atom

Compounds are made of 2 or more elements chemically bonded together

Explanation:

Its right there????

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Importance of pH value in daily life
olganol [36]
Plants require pH to thrive which in turn gives us food.
8 0
2 years ago
When metallic aluminum is added to a solution containing iron(II) sulfate a reaction occurs. What species is being oxidized in t
REY [17]

<u>Answer:</u> Aluminium is getting oxidized in the given chemical reaction.

<u>Explanation:</u>

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

2Al(s)+3FeSO_4(aq.)\rightarrow Al_2(SO_4)_3(aq.)+3Fe(s)

The half cell reactions for the above reaction follows:

<u>Oxidation half reaction:</u>  Al\rightarrow Al^{3+}+3e^-

<u>Reduction half reaction:</u>  Fe^{2+}+2e^-\rightarrow Fe

As, aluminium is loosing 3 electrons to form aluminium cation. Thus, it is getting oxidized. Iron is gaining 2 electrons to form iron anion. Thus, it is getting reduced.

Hence, the oxidized species of the given reaction is aluminium.

4 0
2 years ago
Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
If 25.0 g NO are produced, how many grams of nitrogen gas are used?
ivanzaharov [21]

Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

       N + O ---------> NO

Mole ratio of N to NO is 1:1

Mole of 25.0 g of NO = 25/30.01 = 0.833 moles

Equivalent mole of N = 0.833 moles

Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams

More on stoichiometric calculations can be found here: brainly.com/question/8062886

7 0
1 year ago
PLEASE ANSWER NOW!!!!! WILL GIVE BRAINLIEST!!!
oee [108]

Answer:

a

b

Explanation:

5 0
3 years ago
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