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babymother [125]
2 years ago
15

Help me please:(:(:( with my bellwork for brainiest

Chemistry
1 answer:
Vedmedyk [2.9K]2 years ago
3 0

Answer:

Elements are made of only one kind of atom

Compounds are made of 2 or more elements chemically bonded together

Explanation:

Its right there????

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CaCl2 + Na2CO3 → CaCO3 + 2 NaCl
Nana76 [90]

Answer:

8.45 moles are produced

Explanation:

CaCl₂ + Na₂CO₃ → CaCO₃ + 2 NaCl

From the equation, we can see that for every 1 mole of CaCl₂  and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

to calculate how many moles of CaCO₃ ,we simply multiply multiply each by the 8.45 moles of CaCl₂ which will reacts

these is because for every 1 mole of CaCl₂  and 1 mole Na₂CO₃ will give 1 mole of CaCO₃ and 2 moles of NaCl

therefore we have every 1x8.45(8.45)  mole of CaCl₂  and 1x8.45(8.45) mole Na₂CO₃ will give 1x8.45(8.45) mole of CaCO₃ and 2x8.45(16.9) moles of NaCl

8.45 moles are produced in the reaction

3 0
3 years ago
Read 2 more answers
Suppose that a fictitious element, x, has two isotopes: 59x (59.015 amu) and 62x (62.011 amu). the lighter isotope has an abunda
professor190 [17]

The atomic mass of the element would simply be equal to the sum of the weighted average of each isotope, that is:

atomic mass = 59.015 amu * 0.717 + 62.011 amu * (1 – 0.717)

<span>atomic mass = 59.863 amu</span>

4 0
3 years ago
Seawater is around a 3% aqueous salt solution.
Eduardwww [97]

Answer:

the answer is distillation

3 0
1 year ago
What is the Arrhenius definition of an acid
matrenka [14]

The answer to your question is,

An Arrhenius acid is a type of substance that separates in water to form Hydrogen ions.

-Mabel <3

8 0
3 years ago
Read 2 more answers
. What mass of ammonium chloride must be added to 250. mL of water to give a solution with pH
Eduardwww [97]

The mass of ammonium chloride that must be added is : ( A ) 4.7 g

<u>Given data :</u>

Volume of water ( V )  = 250 mL = 0.25 L

pH of solution = 4.85

Kb = 1.8 * 10⁻⁵

Kw = 10⁻¹⁴

Given that the dissolution of NH₄Cl gives NH₄⁺⁺ and Cl⁻ ions the equation is written as :

NH₄CI  +  H₂O  ⇄  NH₃ + H₃O⁺

where conc of H₃O⁺

[ H₃O⁺ ] = \sqrt{Ka.C}   and Ka = Kw / Kb

∴ Ka = 5.56 * 10⁻¹⁰

Next step : Determine the concentration of H₃O⁺  in the solution

pH = - log [ H₃O⁺ ] = 4.85

∴ [ H₃O⁺ ] in the solution = 1.14125 * 10⁻⁵

Next step : Determine the concentration of NH₄CI in the solution

C = [ H₃O⁺ ]² / Ka

  = ( 1.14125 * 10⁻⁵ )² /  5.56 * 10⁻¹⁰

  = 0.359 mol / L

Determine the number of moles of NH₄CI in the solution

n = C . V

  = 0.359 mol / L  * 0.25 L =  0.08979 mole

Final step : determine the mass of ammonium chloride that must be added to 250 mL

mass = n * molar mass

         = 0.08979 * 53.5 g/mol

         = 4.80 g  ≈ 4.7 grams

Therefore we can conclude that the mass of ammonium chloride that must be added is 4.7 g

Learn more about ammonium chloride : brainly.com/question/13050932

8 0
2 years ago
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