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3 years ago

A) State the Law of Conservation of Matter.

Chemistry

1 answer:

Mariulka [41]3 years ago

4 0

Answer:

matter can either be created nor destroyed but can be transmitted fromone state to another state

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2. A rock occupies a volume of 20 cm and has a mass of 54 grams. Find the density of<br> this rock.

vredina [299]

The answer is 2.7gm/cm^3 . Density is mass divided by volume .

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3 years ago

If you observe a Full Moon on January 12th, on what date would you observe the next New Moon?

AlexFokin [52]

January 19

Explanation:

every first 7 days of a month the moon roughly starts its full moon phase

8 0

3 years ago

A neutralization reaction is a reaction between choose. That results in the formation of choose. And choose.

andrey2020 [161]

Neutralization reaction is the reaction that occur between acid and base.

<h3>What is Neutralization reaction?</h3>

Neutralization reaction is the reaction that take place between acid and base to produce salt and water. For examples HCl react with NaOH to produce NaCl and H2O

Therefore, Neutralization reaction is the reaction between acid and base.

The question is not complete but the option are gotten from another website.

Here are the options.

an acid and a base
a fuel and oxygen
an acid and a metal
a salt and a base

Learn more about neutralization from the link below.

brainly.com/question/4090568

8 0

2 years ago

Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2

Flauer [41]

Answer:

$\boxed{28.81}$

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 58.12 44.01

2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g: 9.511

1. Moles of C₄H₁₀

$\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}$

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

$\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}$

3. Mass of CO₂

$\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}$

8 0

3 years ago

Consider this reaction: HCO3− + H2S → H2CO3 + HS− Which is the Bronsted-Lowry base? H2S HCO3- HS– H2CO3

german

Answer:

hco3

Explanation: bc i said so

3 0

3 years ago

A) State the Law of Conservation of Matter.​

A) State the Law of Conservation of Matter.