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atroni [7]
3 years ago
12

Find the 6th term of the sequence with t1 = -4 and tn = 5tn-1

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
5 0

! hello : <span>
t1 = -4 and tn = 5tn-1
n = 2 : t2 =5t1-1 =5(-4)-1 =-21
n = 3 : t3=5t2-1 =5(-21)-1 =-106
n = 4 : t4 =5t3-1 =5(-106)-1 =-531
n = 5: t5 =5t4-1 =5(-531)-1 =-2656
<span>n = 6 : t2 =5t5-1 =5(-2656)-1 =-13281</span></span>

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Step-by-step explanation:

6 0
2 years ago
Your friend is wrapping 1 meter of twine around a spool with a 2-centimeter diameter. The spool is thin and accommodates only on
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Answer:

a) 6 complete times

b) 19.3%

Step-by-step explanation:

In every turn, the diameter of the twine increases 1 cm.

After the first turn, there is a total wrapped of 3.14*2=6.3 cm.

After the second turn, we have wrapped 6.3+3.14*(2+1)=15.7 cm.

If we continue with these algorithm, we have that after the 6th turn we have 84.8 cm wrapped. <em>This is the last complete turn.</em>

T = 0 D = 2 cm. Wrapped = 6.3 cm. Total wrapped = 6.3 cm.

T = 1         D = 3 cm. Wrapped = 9.4 cm. Total wrapped = 15.7 cm.

T = 2 D = 4 cm. Wrapped = 12.6 cm. Total wrapped = 28.3 cm.

T = 3 D = 5 cm. Wrapped = 15.7 cm. Total wrapped = 44 cm.

T = 4 D = 6 cm. Wrapped = 18.8 cm. Total wrapped = 62.8 cm.

T = 5 D = 7 cm. Wrapped = 22.0 cm. Total wrapped = 84.8 cm.

T = 6 D = 8 cm. Wrapped = 25.1 cm. Total wrapped = 110 cm.

There are left (100-84.8) = 15.2 cm to wrap around the twine, which has a 25.1 cm diameter by now.

The perimeter of the twine is 3.14*25.1=78.8 cm.

The percentage of a complete circle that the last wrapping of the twine will make is:

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4 0
3 years ago
___,36 ,108 ,324 ,972
hjlf
12

First figure out of it is a arithmetic or geometric sequence, in this case it is a geometric sequence because you have to multiply, not add to find the next number.

Divide one number, I'll pick 324 by the number before it, 108, you get three.

Now divide 36 by 3, you get 12.

To check, multiply 12 by 3, you get 36, multiply that by 3, you get 108, and so on and so forth.
3 0
3 years ago
Jennifer utilizo 2/7 de metro de cinta para hacer moños para sus primas. Ahora le quedan 10/21 de metro de cinta. ( problema ver
Vikki [24]

Answer:

x = \frac{16}{21}\,m

Step-by-step explanation:

El enunciado pregunta la cantidad inicial de cinta utilizada por Jennifer, la cual es la suma de la porción utilizada y la porción remanente:

x = \frac{2}{7}\,m + \frac{10}{21}\,m

x = \frac{42}{147}\,m + \frac{70}{147}\,m

x = \frac{112}{147}\,m

x = \frac{16}{21}\,m

6 0
2 years ago
Which fractions are equievalent? a.20/5 b.-20/5 c.20/-5 d. -20/-5 e.- 20/5
pogonyaev

Answer:

D) -20/-5 because a negative divided by a negative is a positive.

Step-by-step explanation:


6 0
3 years ago
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