Answer:
TRUE
Explanation:
Standard temperature is 273K and 350°C is 623K.
V/V' = T/T'
3/6.84 = 273/T'
T' = (273×6.84)/3
=> T' = 623K
So it is true.
Answer:
B) 0.59 M NaCl.
Explanation:
- It is known that the no. of millimoles of NaCl before dilution = the no. of millimoles of NaCl after dilution.
∵ (MV) before dilution = (MV) after dilution.
<em>∴ M after dilution = (MV) before dilution / V after dilution </em>= (3.2 M)(25.0 mL)/(135.0 mL) = <em>0.5926 M ≅ 0.59 M.</em>
D. HNO3 and NaNO3; Pair of substances cannot form a buffered aqueous solution is hno3 and nano3.
More about HNO3 and NaNO3:
The inorganic substance with the formula HNO3 is nitric acid. It is a mineral acid that is quite corrosive. The substance is colourless, but older samples may have a yellow hue from breakdown into nitrogen oxides.
The majority of nitric acid that is sold commercially has a 68% concentration in water. Nitric acid that is flaring when the solution contains more than 86% HNO3.
The chemical with the formula NaNO 3 is sodium nitrate. To distinguish it from regular saltpetre, potassium nitrate, this alkali metal nitrate salt is sometimes known as Chile saltpetre Nitratine, nitratite, are other names.
Learn more about HNO3 here:
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The answer is A
explanation:
We know that the atomic weight of carbon is 12 grams and that of oxygen is 16 grams. Hence we have calculated the mass 5 of carbon in carbon dioxide to be 27.27%.
The answer will be True to this question