<u>Answer:</u> Yes, metals and non-metals forms ionic bonds.
<u>Explanation:</u>
Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.
The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.
<u>For Example:</u> Formation of sodium chloride
Sodium is a metal and is the 11th element of periodic table having electronic configuration of ![[Ne]3s^1](https://tex.z-dn.net/?f=%5BNe%5D3s%5E1)
To form 
ion, this element will loose 1 electron.
Chlorine is a non-metal and is the 17th element of periodic table having electronic configuration of ![[Ne]3s^23p^5](https://tex.z-dn.net/?f=%5BNe%5D3s%5E23p%5E5)
.
To form 
ion, this element will gain 1 electron.
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the compound formed between sodium and chlorine atom is NaCl
Hence, metals and non-metals forms ionic bonds.
Answer:
See explanation
Explanation:
The compound is acetylacetone. This compound is immiscible with water because it is completely nonpolar.
However the introduction of ammonia, leads to the ionization of the specie. In the presence of a base(such as NH3), the molecule acetylacetone is deprotonated and its corresponding anion is formed. This anion can now interact with water and become miscible with it.
Answer:
See attached picture.
Explanation:
Hello!
In this case, since C2H3Cl is an organic compound we need a central C-C parent chain to which the three hydrogen atoms and one chlorine atom provides the electrons to get all the octets except for H as given on the statement.
In such a way, on the attached picture you can find the required Lewis dot structure without formal charges and with all the unshared electron pairs, considering there is a double bond binding the central carbon atoms in order to compete their octets.
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