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Makovka662 [10]
3 years ago
15

Question 2 (1 point)

Chemistry
1 answer:
Alex73 [517]3 years ago
6 0

Answer:

35 amu

Explanation:

In an atom, only masses of protons and neutrons are relevant. electrons are so small in size that their masses are negligible.

The mass of 1 proton/neutron is 1amu.

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How much energy is required to change the temperature of 35.0 g of Lead
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Answer:

Q = 270 Joules (2 sig. figs. as based on temperature change.)

Explanation:

Heat Transfer Equation of pure condensed phase substance => Q = mcΔT

Mixed phase (s ⇄ l melting/freezing, or l ⇄ g boiling/condensation) heat transfer equation => Q = m∙ΔHₓ; ΔHₓ = phase transition constant

Since this is a pure condensed phase (or, single phase) form of lead (Pb°(s)) and not melting/freezing or boiling/condensation, one should use

Q = m·c·ΔT

m = mass of lead = 35.0g

c = specific heat of lead = 0.16J/g°C

ΔT = Temp change = 74°C - 25°C = 49°C

Q = (35.0g)(0.16J/g·°C )(49°C) = 274.4 Joules ≅ 270 Joules (2 sig. figs. as based on temperature change.)

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