Answer : The enthalpy change for the reaction is, 97.7 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given main chemical reaction is,

The intermediate balanced chemical reaction will be,
(1)

(2)

(3)

Now we are multiplying reaction 1 by 2 and reversing reaction 3 and then adding all the equations, we get :
(1)

(2)

(3)

The expression for enthalpy of main reaction will be,



Therefore, the enthalpy change for the reaction is, 97.7 kJ
Answer:
Is this an actual question that you had for school?
Explanation:
Answer:
if i had to guess it would be D
Explanation:
Sorry if im wrong, but i wouldnt have any liquid on atleast one of them so i can compare and contrast the other coins to the regular 1p coins
low melting point means that a low amount of heat is required to melt said substance.
Answer:
French physicist Jacques Charles (1746-1823) studied the effect of temperature on the volume of a gas at constant pressure. Charles's Law states that the volume of a given mass of gas varies directly with the absolute temperature of the gas when pressure is kept constant. The absolute temperature is temperature measured with the Kelvin scale. The Kelvin scale must be used because zero on the Kelvin scale corresponds to a complete stop of molecular motion.
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Figure 11.5.1: As a container of confined gas is heated, its molecules increase in kinetic energy and push the movable piston outward, resulting in an increase in volume.
Mathematically, the direct relationship of Charles's Law can be represented by the following equation:
V
T
=k
As with Boyle's Law, k is constant only for a given gas sample. The table below shows temperature and volume data for a set amount of gas at a constant pressure. The third column is the constant for this particular data set and is always equal to the volume divided by the Kelvin temperature.
Explanation:
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