Answer:
D = 2.38 m
Explanation:
This exercise is a diffraction problem where we must be able to separate the license plate numbers, so we must use a criterion to know when two light sources are separated, let's use the Rayleigh criterion, according to this criterion two light sources are separated if The maximum diffraction of a point coincides with the first minimum of the second point, so we can use the diffraction equation for a slit
a sin θ = m λ
Where the first minimum occurs for m = 1, as in these experiments the angle is very small, we can approximate the sine to the angle
θ = λ / a
Also when we use a circular aperture instead of slits, we must use polar coordinates, which introduce a numerical constant
θ = 1.22 λ / D
Where D is the circular tightness
Let's apply this equation to our case
D = 1.22 λ / θ
To calculate the angles let's use trigonometry
tan θ = y / x
θ = tan⁻¹ y / x
θ = tan⁻¹ (4.30 10⁻² / 140 10³)
θ = tan⁻¹ (3.07 10⁻⁷)
θ = 3.07 10⁻⁷ rad
Let's calculate
D = 1.22 600 10⁻⁹ / 3.07 10⁻⁷
D = 2.38 m
Answer:
Meters
Explanation:"How FAR did the athlete run?"
Also it talked about meters
Answer:
Explanation:
The train travels 5 miles in the east and then 2 miles in the west . Total path length is equal to 5 + 2 = 7 miles . But the displacement is (5 - 2 ) = 3 miles . So displacement ≠ path length
The jogger is running around a circular path . In moving one round on a circular path , path length is equal to the circumference of the circle but the displacement is zero because the starting point and finish point is same.
For the ball rolling down an inclined plane , path length is length of inclined path traveled and displacement is also the same . so in this case path length equals displacement.
For a ball thrown upwards and going downwards , total path length is equal to the total of path gone up and down or twice the height but the displacement is nil if the ball comes back again in the hand.