Answer:
The time taken by the car to get to the other side of an intersection is, t = 4.9 s
Explanation:
Given data,
The acceleration of the car, a = 2.5 m/s²
The initial velocity of the car, u = 0
The distance traveled, s = 30 m
Using the II equations of motion,
<em> S = ut + ½ at²</em>
Therefore,
t = √(2S/a) ( since u = 0)
Substituting the values
t = √(2 x 30 / 2.5)
= 4.9 s
Hence, the time taken by the car to get to the other side of an intersection is, t = 4.9 s
Answer:
D . goggles, a lab coat, heat-proof gloves, and close-toed shoes
Explanation:
To solve this problem, we will use the equation of motion:
v = u + at
where:
v is the final velocity = 117.72 m/sec
u is the initial velocity = zero (body starts falling from rest)
a is the acceleration of the body which is equivalent to acceleration due to gravity = 9.8 m/sec^2
t is the time that we want to calculate
Substitute with the givens in the above equation to get the time as follows:
v = u + at
117.72 = 0 + 9.8t
117.72 = 9.8t
t = 117.72 / 9.8
t = 12.0122 seconds
Answer:
Evan drive at speed = 81.67 m/hr
Explanation:
Normal speed of Evan = 70 m/hr
Time taken by Evan to visit his grandmother = 35 min = hr
Distance covered by Evan = =
= miles
According to the problem, one day Evan was running 5 minutes late. So, the time Evan has to visit his grandmother is 30 mins.
To reach on time, Evan should be drive at the speed :
Speed =
=
= 81.67 m/hr
Answer:
Nuclear binding energy is the energy required to split a nucleus of an atom into its component parts: protons and neutrons, or, collectively, the nucleons. The binding energy of nuclei is always a positive number, since all nuclei require net energy to separate them into individual protons and neutrons.
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