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Bess [88]
3 years ago
7

The force applied when using a simple machine

Physics
2 answers:
jenyasd209 [6]3 years ago
7 0

Answer:

effort

Explanation:

effort is the answer

insens350 [35]3 years ago
7 0

Answer:effort force

Explanation:

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The answer is -7m, but I don’t know how that’s the answer. Can anyone explain?
atroni [7]

Explanation:

At first it is in 14m position but position doesn't matter in displacement, similar case for time taken.

So at first it travels 6m in positive direction.

So displacement= 6m

Then it travels 13 in opposite or negative direction.

So displacement = 6 -13 m = -7 m

Hope it helps ya

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A force of 200N acts between two objects at a certain distance apart .the value of the force when the distance is halved is?
statuscvo [17]

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a 3.18-kg rock is released from rest at a height of 26.6 m. ignore air resistance and determine (a) the kinetic energy at 26.6 m
antiseptic1488 [7]

Answer:

(a) 0 J

(b) 828.96 J

(c) 828.96 J

(d) 828.96 J

(e) 0 J

(f) 828.96 J

Explanation:

Given:

Mass of the rock is, m=3.18\ kg

Initial height of the rock is, h_{i}=26.6\ m

Final height of the rock is, h_f=0\ m

Initial velocity of the rock is, v_i=0\ m/s(Rest)

Acceleration due to gravity is, g=9.8\ m/s^2

(a)

Initial kinetic energy is given as:

K_i=\frac{1}{2}mv_i^2

Plug in the given values and solve for 'K_i'. This gives,

K_i=\frac{1}{2}\times 3.18\times 0^2=0

Therefore, initial kinetic energy is 0 J.

(b)

Initial potential energy is given as:

U_i=mgh_i\\U_i=3.18\times 9.8\times 26.6=828.96\ J

Therefore, initial potential energy is 828.96 J.

(c)

Mechanical energy is equal to the sum of kinetic and potential energy. It is always a constant value. Therefore,

ME=K_i+P_i\\ME=0+828.96=828.96\ J

Therefore, mechanical energy at 26.6 m is 828.96 J.

(d)

Now, at the final height of 0 m, the decrease in potential energy will be equal to the increase in the kinetic energy. In other words, the potential energy at the start will be converted to kinetic energy at the bottom.

Therefore, kinetic energy at the 0 m is given as:

K_f=U_i=828.96\ J

(e)

Potential energy at the final height is given as:

P_f=mgh_f=3.18\times 9.8\times 0=0\ J

Therefore, final potential energy is 0 J.

(f)

Total mechanical energy is a constant and doesn't depend on the height.

So, total mechanical energy at 0 m is same as that at 26.6 m.

Total mechanical energy is 828.96 J.

8 0
3 years ago
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