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garik1379 [7]
4 years ago
5

What is the force of friction acting on this box? N What is the net force acting on this box? N to the

Physics
2 answers:
Zanzabum4 years ago
5 0

Answer: -3, 12, right

Explanation:

n/a just did the test

e-lub [12.9K]4 years ago
3 0

Answer:

-3,12,right

Explanation:

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A spring loaded toy shoots straight upward with a velocity of 4.5 m/s. Determine the maximum height it reaches. Determine the ti
Angelina_Jolie [31]

Recall that

{v_y}^2-{v_{0y}}^2=2a_y(y-y_0)

At its maximum height y_{\mathrm{max}}, the toy will have 0 vertical velocity, so that

-\left(4.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}

\implies y_{\mathrm{max}}=1.0\,\mathrm m

For the toy to reach this maximum height, it takes time t such that

\dfrac{0+v_0}2t=y_{\mathrm{max}}\implies t=0.46\,\mathrm s

which means it takes twice this time, i.e. t=0.92\,\mathrm s, for the toy to reach its original position.

The velocity of the toy when it falls 1.0 m below its starting point is

{v_y}^2-\left(4.5\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(0-1.0\,\mathrm m)

\implies{v_y}^2=39.85\,\dfrac{\mathrm m^2}{\mathrm s^2}

\implies v_y=-6.4\,\dfrac{\mathrm m}{\mathrm s}

where we took the negative square root because we expect the toy to be moving in the downward direction.

6 0
3 years ago
True or False? Materials that are good conductors of heat are usually poor conductors of electricity.
alexandr402 [8]

False

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How much heat is needed to raise the temperature of 100 g of water by 50 C, if the specific heat of water is 4,184 J/kg.C?
Yuliya22 [10]

Heat required to raise the temperature of water is given as

Q = ms\Delta T

here we have

m = 100 g = 0.100 kg

s = 4183 J/kg C

\Delta T = 50 ^0 C

now we can use the above equation

Q = 0.100 * 4184 * 50

Q = 20920 J

so here it requires 20920 J heat to raise the temperature of 100 g water by 50 degree C

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3 years ago
A force of 1.00 x 10^2 pounds acts at an angle of 60.0° to the x-axis. (The force is accurate to 3 significant figures.) What ar
tamaranim1 [39]

Answer:

Fx= 50.0 Pounds : Components of the force along the x-axis

Fy= 86.6 Pounds : Component of the force along the y-axis

Explanation:

Conceptual Analysis

To find the components (Fx, Fy) of the total force (F), we apply the trigonometric concepts for a right triangle, where the perpendicular sides of the triangle are the components (Fx, Fy) of the force (F), the hypotenuse (h) is the magnitude of the total force F and β is the angle that forms the horizontal component with the hypotenuse.

Formulas

cos β : x/h  :    x: side adjacent to the β angle  h: hypotenuse  (1)

sin β = y/h  :    y: side opposite to the β angle  h: hypotenuse  (2)

Known Data

Known data

F= 1.00 * 10² pounds  = 100 pounds :  magnitude of total force

β =  60.0° to the x-axis. : Angle that forms the force with the x-axis

Problem Development

We apply the formula 1 to calculate horizontal component (Fx)

cos β :Fx/F

Fx= F cosβ  = 100*cos 60° = 50.0 Pounds

We apply the formula 2 to calculate vertical component (Fy)

sin β = Fy/F

Fy= F sinβ = 100*sin 60° = 86.6 Pounds

6 0
4 years ago
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