On a different day the same car enters a 420-m radius horizontal curve on a rainy day when the coefficient of static friction be
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Part A)
As we know see the graph
It travel from point A to G
so the displacement is from A to G directly
its 10 m towards North
Part B)
total distance we have to calculate total path length
so from A to B = 2 squares
from B to C = 4 squares
C to D = 1 square
D to E = 5 square
E to F = 1 square
F to G = 4 square
total distance = 2 + 4 + 1 + 5 + 1 + 4 = 17 square
1 square = 10 m
total distance = 170 m
PART C)
As we know that average speed is defined as
as we know that
total time = 45 s
total distance = 170 m
from above formula now
PART D)
As we know that average velocity is defined as
here we have
displacement = 10 m north
time = 45 s
now from above equation
Part E)
As we know that average acceleration is rate of change in the velocity
so here we have
final velocity = 3 m/s
initial velocity = 4 m/s
time = 3 s
now from the equation