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Kitty [74]
3 years ago
5

On a different day the same car enters a 420-m radius horizontal curve on a rainy day when the coefficient of static friction be

tween its tires and the road is 0.250. What is the maximum speed at which the car can travel around this curve without sliding?
Physics
1 answer:
Inessa05 [86]3 years ago
7 0

Answer:

centripetal force points towards the center of the circle, and force friction points the opposite way. Set the two equal to each other

Force Normal * coefficient of static friction = mass*velocity^2/radius

(mg)Us = mv^2/r

mass isn't given in the problem because it cancels on both sides.

9.8Us = V^2/r

9.8(.600) = v^2/300

v^2 = 1764

v = 42 m/s

the man

Oct 30, 2015

A car enters a 300-m radius flat curve on a rainy day when the coefficient of static friction between its tires and the road is 0.600. What is the maximum speed which the car can travel around the curve without sliding?

m/s 33.1 0

m/s 29.6 0

m/s 42

m/s 24.8

Explanation:

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A fisherman is fishing from a bridge and is using a "42.0-N test line." In other words, the line will sustain a maximum force of
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Answer:

(a) 42 N

(b)36.7 N

Explanation:

Nomenclature

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Problem development

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∑Fy =0

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W = 42N

(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²

We apply Newton's second law because the system moves at constant acceleration:

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∑Fy =m*a

m= W/g , m= W/9.8 ,  m:fish mass , W: fish weight g:acceleration due to gravity

F-W= ( W/9.8 )*a

42-W=  ( W/9.8 )*1.41

42= W+0.1439W

42=1.1439W

W= 42/1.1439

W= 36.7  N

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Answer:

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