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3 years ago

5

On a different day the same car enters a 420-m radius horizontal curve on a rainy day when the coefficient of static friction be

tween its tires and the road is 0.250. What is the maximum speed at which the car can travel around this curve without sliding?

1 answer:

Inessa05 [86]3 years ago

7 0

Answer:

centripetal force points towards the center of the circle, and force friction points the opposite way. Set the two equal to each other

Force Normal * coefficient of static friction = mass*velocity^2/radius

(mg)Us = mv^2/r

mass isn't given in the problem because it cancels on both sides.

9.8Us = V^2/r

9.8(.600) = v^2/300

v^2 = 1764

v = 42 m/s

the man

Oct 30, 2015

A car enters a 300-m radius flat curve on a rainy day when the coefficient of static friction between its tires and the road is 0.600. What is the maximum speed which the car can travel around the curve without sliding?

m/s 33.1 0

m/s 29.6 0

m/s 42

m/s 24.8

Explanation:

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3 years ago

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1

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Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

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An object is pushed from rest across a sheet of ice, accelerating at 8.0 m/s^2 [E] over a displacement of 1.05 m [E]. The object

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Answer:

$D_T=18.567m$

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From the question we are told that:

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Generally the equation for Distance to stop is mathematically given by

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$D_T=18.567m$

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