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Anon25 [30]
3 years ago
8

LINEAR, QUADRATIC, EXPONENTIAL REVIEW: QUESTION 3 Find the equation of the line that has a slope of 2 and passes through the poi

nt (1, 7).
Mathematics
1 answer:
Whitepunk [10]3 years ago
4 0

The point-slope form:

y-y_1=m(x-x_1)

We have

m=2,\ (1,\ 7)

Substitute:

y-7=2(x-1)\qquad|\text{use distributive property}\\\\y-7=2x-2\qquad|+7\\\\y=2x+5\qquad|-5\\\\y-5=2x\qquad|-y\\\\2x-y=-5

<h3>Answer:</h3><h3>point-slope form: y - 7 = 2(x - 1)</h3><h3>slope-intercept form: y = 2x + 5</h3><h3>standard form: 2x - y = -5</h3>
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PLEASE HELP ASAP!!!!
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Let us model this problem with a polynomial function.

Let x =  day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.

Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅

Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
|   1     1    1    1    1  |  | a₁ |      | 42 |
| 2⁴  2³  2²  2¹  2⁰  |  | a₂ |      | 26 |
| 3⁴  3³  3²  3¹  3⁰   |  | a₃ |  =  | 61 |
| 4⁴  4³  4²  4¹  4⁰   |  | a₄ |      | 65 |
| 5⁴  5³  5²  5¹  5⁰  |  | a₅ |      | 56 |

When this matrix equation is solved in the calculator, we obtain
a₁ =      4.1667
a₂ =  -55.3333
a₃ =  253.3333
a₄ =  -451.1667
a₅ =   291.0000

Test the solution.
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y(2) = 26
y(3) = 61
y(4) = 65
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The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.

Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631


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