X=length
y=width
Area (rectangle)=length x width
we suggest this system of equations:
y=x/5
xy=9/20
solve this system of equations by substitution method:
x(x/5)=9/20
x²/5=9/20
Least common multiple=20
4x²=9
x²=9/4
x=⁺₋√(9/4)
we have two solutions:
x₁=-3/2 it does not validate
x₂=3/2 ⇒y=x/5=(3/2)/5=3/10
The dimensions of the lake are:
lengh=3/2 miles
width=3/10 miles
to check:
Area=3/2 miles x 3/10 miles=9/20 miles².
width is 1/5 the length of the lake ⇒ 3/10 miles=(3/2) /5 miles
Answer:
5{z}^{3}-222-9{z}^{2}5z
3
−222−9z
2
Step-by-step explanation:
1 Collect like terms.
5{z}^{3}+(-224+2)-9{z}^{2}5z
3
+(−224+2)−9z
2
2 Simplify.
5{z}^{3}-222-9{z}^{2}5z
3
−222−9z
2
Done
Answer:
58
Step-by-step explanation:
You just have to replace the value of n with 4.
C(n) = 46 + 3n
C(4) = 46 + 3(4)
= 46 + 12
= 58
8(number of soup) times 3 =x (number of vegetable cans)
Answer:
<em>I earned $856 on the first day</em>
Step-by-step explanation:
Let's call
x = earning on the second day
2x = earnings on the first day
3x = earnings on the third day
The total earnings are $2568, thus
x + 2x + 3x = 2568
Simplifying:
6x = 2568
Dividing by 6:
x = 2568/6
x = 428
I earned $428 on the second day.
2x = 2*$428 = $856
I earned $856 on the first day
