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serg [7]
3 years ago
12

Calculate the average atomic mass of rubidium. Rubidium has two isotopes, 85Rb and 87Rb. 85Rb has an atomic mass of 84.912 amu a

nd occurs at an abundance of 72.17%. 87Rb has an atomic mass of 86.909 amu and occurs at an abundance of 27.83%. Show your work.
Chemistry
1 answer:
astraxan [27]3 years ago
4 0
<span>Answer : The average atomic mass of rubidium = 85.468 Explanation: Given that 85Rb isotope has atomic mass of 84.912amu with abundance of 72.17% therefore we get 84.912 x 0.7217 = 61.281 and 87Rb isotope has atomic mass of 86.909 with abundance of 27.83% hence we get 86.909 x 0.2783 = 24.187 Thus we get 61.281 + 24.187 = 85.468 as the average atomic mass of Rubidium.</span>
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Calculate the total volume of gas (at 119 ?c and 731 mmhg produced by the complete decomposition of 1.71 kg of ammonium nitrate.
Shtirlitz [24]
The reaction is:

NH4 (NO3) (s) ⇄ N2O (g) + 2 H2O (g)

This means that 1 mol of NH4 (NO3)s produces 3 moles of gases.

Now find the number of moles in 1.71 kg of NH4 (NO3)

Molar mass = 2*14g/mol + 4 * 1g/mol + 3*16g/mol = 80 g/mol

# moles = mass / molar mass = 1710 g / 80 g/mol = 21.375 mol of NH4(NO3)

We already said that every mol of NH4(NO3) produces 3 moles of gases, then the number of moles of gases produced is 3 * 21.375 = 64.125 mol

Now use the equation for ideal gases to fin the volume

pV = nRT => V = nRT / p = (64.125 mol)(0.082atm*liter / K*mol) * (119 +273)K / (731mmHg *1 atm/760mmHg) =

V = 2143.01 liters
4 0
3 years ago
Correct answer will be marked brainliest!
tigry1 [53]

Answer:

0.0660 moles

Explanation:

Change torr to atm and change celcius to kelvin.

(1.35L)(.987 atm)/(0.08206 L atm /mol k)(290k)

= 0.0660 mol

4 0
3 years ago
This what happen when climate changes
zysi [14]

if you are talking about the climate change of today as in the heat your answer would be ,because the green house gases are trapping in the heat and reflecting it back down it disrupts the temperature everywhere. so the hot weather will become even HOTTER the cold weather will become warmer of come to late ,and the places such as Greenland and Antarctica which are covered in snow will start to melt making the whole globe more hot year by year

8 0
4 years ago
Convert 4.50 e23 atoms of CO to grams.
hichkok12 [17]

Answer:

10.4664 grams of CO

Explanation:

Remark

There's a couple of things you must look out for in this question.

1. The use of the term atoms. There are 2 atoms in each mol of CO

2. You need to divide by 2 to find the number of molecules which will lead to moles.

<u>Step one</u>

Divide the number of atoms by 2

4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.

<u>Step Two</u>

Find the number of moles of CO

1 mol of anything is 6.02 * 10^23 molecules in this case

x  = 2.25 * 10^23 molecules

1/x = 6.02 * 10^23/2.25 * 10 ^23            Cross multiply

1 * 2.25 * 10^23 = 6.02*10^23 * x           Divide by 6.02 * 10^23

2.25 * 10 ^ 23 / 6.02 * 10^23 = x

x = .3738 moles of CO

<u>Step Three</u>

Find the gram molecular mass of CO

C = 12

O = 16

1 mole = 12 + 16  = 28 grams.

<u>Step Four</u>

Find the number of gram in 0.3738 mols

1 mol = 28 grams

0.3738 mol = x                Cross multiply

x = 28 * 0.3738

x = 10.4664 grams

7 0
3 years ago
How much heat is required to raise the temperature of 91.5 g of water from its melting point to its boiling point? Express your
gizmo_the_mogwai [7]

Answer:

38.2836 kJ

Explanation:

Mass = 91.5g

Initial Temperature = melting point = 0 C = 273 K (upon converting to kelvin)

Final Temperature = Boiling point = 100 C = 373 K

Heat = ?

They are related by the equation;

H = mCΔT

ΔT = Final - Initial Temperature = 373 - 273 = 100 K

C = specific heat capacity = 4.184 J /gK

H = 91.5 * 4.184 * 100

H = 38283.6 J

To convert to kilojoules, divide by 1000. This leaves us with;

H = 38283.6 / 1000 = 38.2836 kJ

3 0
3 years ago
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