<span>He then drank 35 percent of the water in the container
so 65% left in in the container
0.65 x 500 = 325 </span><span>milliliter
answer
</span>325 milliliter of water left in the container
Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.




Therefore, amount of the material left after 10 days would be 0.5 kg.





Therefore, amount of the material left after 20 days would be 0.25 kg.
0.3 is 3 tenths.
The order of "ths" is tenths, hundredths, thousandths.
Since there are no numbers after the 3, you simply have to add 2 zeros to make it 300 thousandths.
0.300<span />
Answer:
(x,y) --> (-1, -3)
Step-by-step explanation:
Solve by elimination...
2x - 3y = 7
4x + y = -7 (times 3; so -3y and 3y cancel out)
2x - 3y = 7
12x + 3y = -21
2x = 7
12x = -21
add together...
14x = -14
x = -1
plug x into one of the original equations and solve for y...
-2 - 3y =7
-3y = 9
y = -3
Answer:
89percent
Step-by-step explanation:
i am not good at math but what ever