The volume of carbon dioxide produced is : 5.4 L
<u>Given data:</u>
moles of propane = 0.080 moles
<h3>Determine the volume of Carbon dioxide produced </h3>
The chemical reaction
C₃H₈ + 5O₂ ---- > 3CO₂ + 4H₂O
From the reaction
I mole of C₃H₈ = 3CO₂
0.080 moles of C₃H₈ = 3 * 0.080 = 0.24
Applying the equation below to determine the volume of CO₂
Pv = nRT
= 0.24 * R * T
v = ( 0.24 * 8.314 * 273 ) / 1 atm
= 544.7 ml = 5.4 L
Hence we can conclude that The volume of carbon dioxide produced is : 5.4 L
Learn more about Propane burning at STP : brainly.com/question/11903456
This should be under biology.
To transport the substance inside the cell when the concentration inside the cell is already higher than outside the cell would require active transport because the substance would be moving against its concentration gradient.
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Answer:
X(SF₆) = 0.361
X(N₂O) = 0.639
Explanation:
Step 1: Calculate the moles of each gas
We use the following expression.
n = m / M
where,
SF₆: 16.7 g / 146.06 g/mol = 0.114 mol
N₂O: 8.88 g / 44.01 g/mol = 0.202 mol
The total number of moles is 0.114 mol + 0.202 mol = 0.316 mol
Step 2: Calculate the mole fraction of each gas
We use the following expression.
X = moles of gas / total number of moles
X(SF₆) = 0.114 mol / 0.316 mol = 0.361
X(N₂O) = 0.202 mol / 0.316 mol = 0.639
Insulation wraps because independent is the variable you are changing to affect the dependent variable (what you are measuring)