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love history [14]
3 years ago
10

A gas fills a balloon at a temperature of 27 C and 101.325 kPa of pressure. What will the pressure of the balloon be if the gas

is heated to 127 C?
Chemistry
1 answer:
JulijaS [17]3 years ago
3 0

135.1‬kPa

Explanation:

Given parameters:

T1 = 27°C

P1  = 101.325 kPa

T2 = 127°C

Unknown:

P2 = ?

Solution:

Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.

 At constant volume:

           \frac{P1}{T1}  = \frac{P2}{T2}

P1 is the initial pressure

T1 is the initial temperature

P2 is the final pressure

T2 is the final temperature

  Take the given temperature to K

T1 = 27 + 273 = 300K

T2 = 127 + 273  = 400K

 Input the variables:

    \frac{101.325}{300}  = \frac{P2}{400}

  P2 = 135.1‬kPa

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

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At a given temperature the vapor pressure of pure liquid benzene and toluene are 745 torr and 290 torr, respectively. A solution
IRISSAK [1]

Answer:

Vapour pressure of benzene over the solution is 253 torr

Explanation:

According to Raoult's law for a mixture of two liquid component A and B-

vapour pressure of a component (A) in solution = x_{A}\times P_{A}^{0}

vapour pressure of a component (B) in solution = x_{B}\times P_{B}^{0}

Where x_{A},x_{B} are mole fraction of component A and B in solution respectively

P_{A}^{0},P_{B}^{0} are vapour pressure of pure A and pure B respectively

Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr

So, vapour pressure of benzene in solution = 0.340\times 745 torr

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Solution attached.

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Upon heating a copper sample will expand, leading to a lower density? <br><br>A) True<br>B) False
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Answer;

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Explanation;

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