HELP ME FAST PLEASE

Factor the expression over the complex numbers.<br><br><img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B18" id="TexFormula1

AleksAgata [21]

Here we are given the expression:

$x^{2}+18$

Now let us equate it to zero to find x first,

$x^{2}+18=0$

Now subtracting 18 from the other side,

$x^{2}=-18$

taking square root on both sides,

So we will get two values of x as ,

$x=3\sqrt{-2}$

$x=-3\sqrt{-2}$

Now we can write square root -1 as i,

So our factors become,

$x=3i\sqrt{2}$

$x=-3i\sqrt{2}$

Answer:

The final factored form becomes,

$(x+3i\sqrt{2})(x-3i\sqrt{2})$

7 0

3 years ago

Read 2 more answers

Please show me step by step

AURORKA [14]

Answer:

Step-by-step explanation:

Picture

7 0

2 years ago

The height if a pyramid is the perpendicular distance between the base and the top of the pyramid. Which is greater, the height

kvasek [131]

The slant would be greater than the height because it is the hypotenuse and it is always greater than the legs.

Hope this helps

6 0

3 years ago

In a survey of randomly selected 3,900 family-owned businesses with revenues exceeding $1 million a year, it was found that 1,91

Maurinko [17]

Answer:

a) The 90% confidence interval to estimate the proportion of family-owned businesses without strategic business plans is (0.4768, 0.5032). This means that we are 90% sure that the true proportion of all family-owned businesses without strategic business plans is between these two values.

b) Wider

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

In a survey of randomly selected 3,900 family-owned businesses with revenues exceeding $1 million a year, it was found that 1,911 of them had no strategic business plan.

This means that $n = 3900, \pi = \frac{1911}{3900} = 0.49$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.645\sqrt{\frac{0.49*0.51}{3900}} = 0.4768$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.645\sqrt{\frac{0.49*0.51}{3900}} = 0.5032$

The 90% confidence interval to estimate the proportion of family-owned businesses without strategic business plans is (0.4768, 0.5032). This means that we are 90% sure that the true proportion of all family-owned businesses without strategic business plans is between these two values.

Question b:

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

The higher the confidence level, the higher the value of z, thus the higher the margin of error and the interval is wider. Thus, a 99% confidence interval is wider than a 90% confidence interval.

3 0

2 years ago

Derek weighs 155 pounds and drives a utility vehicle that can carry no more than 220 pounds. He plans to use his utility vehicle

liraira [26]

By the looks of this the answer is E

Derek weighs 155
155+220

8 0

3 years ago