The answer is C) 3/4
Let's analyze separately each of the traits:
Parental generation: AA x Aa
F1 generation: AA AA Aa Aa
So, all progeny will <span>phenotypically resemble the first parent.
</span>Parental generation: BB x bb
F1 generation: Bb Bb Bb Bb
So, all progeny will <span>phenotypically resemble the first parent.
</span>
Parental generation: Cc x Cc
<span>F1 generation: CC Cc Cc cc
</span>Only 3 (CC, Cc, Cc) out of 4 progeny will <span>phenotypically resemble the first parent.
The genotypes for first two traits will not affect </span>phenotypical resemblance to the first parent. So, it only counts the third trait, for which the chance to have progeny that <span>phenotypically resemble the first parent is 3/4.</span>
Cells become haploid in cytokinesis of meiosis one because the chromosomes have divided.
Distribute the A to the B and the b, then the a to the B and the b. You should get four different possible combinations: AB Ab aB ab. These would then be used to set up one side of a punnett square, and the other parent's genotype would be set up the same, then put on the other side of the punnett square.
