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Andrej [43]
3 years ago
11

Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the pro

geny will be expected to phenotypically resemble the first parent?
A) 1/4
B) 1/8
C) 3/4
D) 3/8
E) 1
Biology
1 answer:
galina1969 [7]3 years ago
7 0
The answer is C) 3/4

Let's analyze separately each of the traits:

Parental generation: AA x Aa
F1 generation:       AA AA Aa Aa
So, all progeny will <span>phenotypically resemble the first parent.

</span>Parental generation: BB x bb
F1 generation:       Bb Bb Bb Bb
So, all progeny will <span>phenotypically resemble the first parent.
</span>
Parental generation: Cc x Cc
<span>F1 generation:       CC Cc Cc cc
</span>Only 3 (CC, Cc, Cc) out of 4 progeny will <span>phenotypically resemble the first parent.

The genotypes for first two traits will not affect </span>phenotypical resemblance to the first parent. So, it only counts the third trait, for which the chance to have progeny that <span>phenotypically resemble the first parent is 3/4.</span>
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Answer:

Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg Capillary colloid osmotic pressure (OPc) = 25 mmHg Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg. The net filtration pressure at this point in the capillary is <u>7mmHg.</u>

Explanation:

  • Data:

Capillary hydrostatic pressure (HPc) = 30 mmHg

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Net filtration pressure= hydrostatic pressure gradient -  Oncotic pressure gradient

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