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marysya [2.9K]
3 years ago
11

What is the sum, in lowest terms?

Mathematics
2 answers:
klasskru [66]3 years ago
8 0
I think it’s The answer is B
I am Lyosha [343]3 years ago
7 0

Answer:

ts of the triangle in terms of x? Give your awns

Step-by-step explanation:

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HELP ME, PLZ. 100 POINTS !!!
marta [7]

Answer:

x=2√5/5

x=-2√5/5

Step-by-step explanation:

13√(2√5/5)^2-(2√5/5)^4+9√(2√5/5)^2+(2√5/5)^4=16

13√(4×5/25)-(16×25/625)+9√(4×5/25)+(16×25/625)

13√(4/5)-(16/25)+9√(4/5)+(16/25)

13√(4/25)+9√(36/25)

13×2/5+9×6/5

26/5+54/5

16=16 (proven)

3 0
2 years ago
A jar contains some bacteria. Every day the number of bacteria
svp [43]

Answer:

Day 2

Step-by-step explanation:

Every 20 days, one jar is full.

To find when it was 1/8 full, we multiply the 20 days by 1/8.

20 x 1/8 =  2

Day 2

3 0
2 years ago
What is the answer show work -15 + n = -27
tangare [24]
<span>-15 + n = -27
Add 15 to both sides so that the only thing remaining on one side is the variable n.
Final Answer: n= -12</span>
8 0
2 years ago
Read 2 more answers
The model shows 1/2 . Which of the following correctly models and gives the quotient of 1/2 / 3/8 ?
GenaCL600 [577]
1/2 / 3/8 =
1/2 * 8/3 =
1*8 / 2/3 =
8/6 = 4/3 your answer
8 0
3 years ago
Read 2 more answers
On day two of a study on body temperatures, 106 temperatures were taken. Suppose that we only have the first 10 temperatures to
NemiM [27]

Answer:

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 10 - 1 = 9

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.2622

The margin of error is:

M = T*s = 2.2622*0.3 = 0.68

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.44 - 0.68 = 97.76 ºF

The upper end of the interval is the sample mean added to M. So it is 98.44 + 0.68 = 99.12 ºF

The 95% confidence interval for the mean of all body temperatures is between 97.76 ºF and 99.12 ºF

4 0
3 years ago
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