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Daniel [21]
2 years ago
6

Kindred invested $38,976 into first company his investment decreased by 3.5% each years over the first 3 years. Which exponentia

l decay model could use to determine the amount his investment will be worth if in continue to decrease at the same rate?
Mathematics
1 answer:
tankabanditka [31]2 years ago
3 0

Answer:

35,025.08 x 0.965 ^ X = Y

Step-by-step explanation:

Given that Kindred invested $ 38,976 into First company, and his investment decreased by 3.5% each year over the first 3 years, to determine which exponential decay model could use to determine the amount his investment will be worth if it continues to decrease at the same rate the following calculation must be performed:

100 - 3.5 = 96.5

38,976 x 0.965 ^ 3 = 35,025.08

Thus, after 3 years of losses, the value of the account will be $ 35,025.08. In turn, if we wanted to determine the amount his investment will be worth if it continues to decrease at the same rate, the following equation should be applied:

35,025.08 x 0.965 ^ X = Y

In this case, X will be the number of years the investment has fallen, and Y will be the value of said investment after the years of decline.

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1. Which point on the axis satisfies the inequality y
grigory [225]

Answer:

1) Point (1,0) -----> see the attached figure N 1

2) The value of x is 4

3) I quadrant

4) (1,1)

5)  y>-5x+3

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point (1,0) is included in the shaded area

Part 2)

we have

x-2y\geq 4

see the attached figure N 2

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line x-2y= 4

For y=0

Find the value of x

x-2(0)= 4  

x=4

The solution is x=4

Part 3)

we have

x\geq 0 -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

y\geq 0 -----> inequality B

The solution of the inequality B is in the first and second quadrant

so

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

y\geq 4x-5

we know that

If a ordered pair is a solution  of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

<u>case A)</u> point (3,4)

Substitute the value of x and y in the inequality

x=3,y=4

4\geq 4(3)-5

4\geq 7 ------> is not true

therefore

the point (3,4) is not a solution of the inequality

<u>case B)</u> point (2,1)

Substitute the value of x and y in the inequality

x=2,y=1

1\geq 4(2)-5

1\geq 3 ------> is not true

therefore

the point  (2,1) is not a solution of the inequality

<u>case C)</u> point (3,0)

Substitute the value of x and y in the inequality

x=3,y=0

0\geq 4(3)-5

0\geq 7 ------> is not true

therefore

the point  (3,0) is not a solution of the inequality

<u>case D)</u> point (1,1)

Substitute the value of x and y in the inequality

x=1,y=1

1\geq 4(1)-5

1\geq -1 ------> is true

therefore

the point  (1,1) is  a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point (3,0)

The x-intercept is a positive number

The solution is the shaded area above the dashed line

so

the equation of the line is y=-5x+3

The inequality is  y>-5x+3

3 0
3 years ago
Read 2 more answers
The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10
Rama09 [41]

Answer:

a) E(X) = 6.45

b) E(X^{2} )= 57.25

c) V(X) = 15.648

d) E(3X + 2) = 21.35

e) E(3X^{2} +2) = 173.75

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) E(X) = \sum xP(x)

E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45

b)

E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\  E(X^{2} )= 57.25

c)

V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648

d)

E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35

e)

E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75

f)

V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832

g)

E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45

h)

V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648

6 0
3 years ago
Integrate with respect to x <br><br> 1/√(1-2x)
Ilia_Sergeevich [38]

Answer:

-√(1 - 2x) + C

Step-by-step explanation:

1/√(1-2x)

We want to integrate it. Thus;

∫1/√(1 - 2x) dx

Let u = 1 - 2x

Thus;

du/dx = -2

Thus, dx = -½du

Thus,we now have;

-½∫1/√(u) du

By application of power rule, we will now have;

-½∫1/√(u) du = -√(u) + C

Plugging in the value of u, we will have;

-√(1 - 2x) + C

3 0
2 years ago
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Nutka1998 [239]

Answer:

5)m=11/10

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Step-by-step explanation:

4 0
2 years ago
) The correlation between a car’s engine size and its fuel economy (in mpg) is r= -0.774. What fraction of the variability in fu
Zolol [24]

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Given that, r= -0.774.

To solve such problems we must know about the fraction of the variability in data values or R-squared.

<h3>What fraction of the variability in fuel economy is accounted for by the engine size?</h3>

The fraction by which the variance of the dependent variable is greater than the variance of the errors is known as R-squared.

It is called so because it is the square of the correlation between the dependent and independent variables, which is commonly denoted by “r”  in a simple regression model.

Fraction of the variability in data values = (coefficient of correlation)²= r²

Now, the variability in fuel economy = r²= (-0.774)²

= 0.599076%= 59.91%

Hence, the fraction of the variability in fuel economy accounted for by the engine size is 59.91%.

To learn more about the fraction of the variability visit:

brainly.com/question/2516132.

#SPJ1

3 0
1 year ago
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